Question

我实际上是想在C中做一个简单的Tic Tac Toe游戏（经典..）。除了我的一个函数之外，一切都还可以：getPlayerInput。我把它放在这里：

#include <stdio.h>
#define N 3
    void getPlayerInput(int player, int *row, int *col, char board[N][N]){

        if(player==1){
            printf("It is player %d turn, please choose an empty space: \n", player);
            scanf("%d %d", row, col);
            if((*row>=1) && (*row<=N) && (*col>=1) && (*col<=N) && (board[(*row-1)][(*col-1)] == '_')){
                board[(*row-1)][(*col-1)]='O';
            }
            while((*row-1)<1 || (*row-1)>N || (*col-1)<1 || (*col-1)>N || (board[(*row-1)][(*col-1)] != '_')){
                    printf("This space is illegal, please choose another: \n");
                    scanf("%d %d", row, col);
                    if((*row>=1) && (*row<=N) && (*col>=1) && (*col<=N) && (board[(*row-1)][(*col-1)] == '_')){
                            board[(*row-1)][(*col-1)]='O';
                    }
            }
        }
        if(player==2){
            printf("It is player %d turn, please choose an empty space: \n", player);
            scanf("%d %d", row, col);
            if((*row>=1) && (*row<=N) && (*col>=1) && (*col<=N) && (board[(*row-1)][(*col-1)] == '_')){
                board[(*row-1)][(*col-1)]='X';
            }
            while((*row-1)<1 || (*row-1)>N || (*col-1)<1 || (*col-1)>N || (board[(*row-1)][(*col-1)] != '_')){
                    printf("This space is illegal, please choose another: \n");
                    scanf("%d %d", row, col);
                    if((*row>=1) && (*row<=N) && (*col>=1) && (*col<=N) && (board[(*row-1)][(*col-1)] == '_')){
                            board[(*row-1)][(*col-1)]='X';
                    }
            }
        }
    }

我的问题是“这个空间是非法的，请选择另一个”。我试着做了一段时间，但它不起作用..我不明白..

当玩家进入不良位置（离开网格或其他地方）时，他必须重新输入一个位置。

有什么想法解决这个问题吗？

先谢谢。

修改1：

void getPlayerInput(int player, int *row, int *col, char board[N][N]){

    if((*row-1)<1 || (*row-1)>N || (*col-1)<1 || (*col-1)>N || (board[(*row-1)][(*col-1)] != '_')){
        printf("This space is illegal, please choose another: \n");
        scanf("%d %d", row, col);
    }

    if(player==1){
        printf("It is player %d turn, please choose an empty space: \n", player);
        scanf("%d %d", row, col);
        if((*row>=1) && (*row<=N) && (*col>=1) && (*col<=N) && (board[(*row-1)][(*col-1)] == '_')){
            board[(*row-1)][(*col-1)]='O';
        }
    }
    if(player==2){
        printf("It is player %d turn, please choose an empty space: \n", player);
        scanf("%d %d", row, col);
        if((*row>=1) && (*row<=N) && (*col>=1) && (*col<=N) && (board[(*row-1)][(*col-1)] == '_')){
            board[(*row-1)][(*col-1)]='X';
        }
    }
}

Answer 1

条件中存在“一次性”错误;假设您输入一个'合法'坐标，其中行为1.位置设置，但while循环仍然输入，因为(*row-1)<1为真;也许它应该是*row<1，这是不正确的否定。也许坐标约定在某个时刻从0基础变为1基础。

Tic Tac Toe游戏中的C [帮助功能]

1 个答案: