Question

我是Oracle新手。我能够执行：

SELECT X, Y, Z. 
FROM SCH2.TAB_A A JOIN SCH2.TAB_B B ON A.CODE = B.CODE
LEFT OUTER JOIN SCH2.MY_V MV ON MV.CODE = B.CODE
WHERE  MV.STATUS = 'A';

但是当我试图将这个SELECT语句放在视图中时，我收到错误：

ORA-00942：表或视图不存在

CREATE OR REPLACE VIEW SCH1.NEW_V AS
SELECT X, Y, Z. 
FROM SCH2.TAB_A A JOIN SCH2.TAB_B B ON A.CODE = B.CODE
LEFT OUTER JOIN SCH2.MY_V MV ON MV.CODE = B.CODE
WHERE  MV.STATUS = 'A';
/

尝试谷歌，

SQL Error: ORA-00942 table or view does not exist

http://www.techonthenet.com/oracle/errors/ora00942.php

但仍然无法解决。如果我能够运行查询，为什么我在尝试将其放入View中时会出现错误。

Answer 1

检查您是否具有直接访问权限，而不是通过角色：

SQL> create user sch1 identified by sch1;

SQL> create role scott_acc;

SQL> grant select on scott.emp to scott_acc;

SQL> grant scott_acc to sch1;

SQL> create or replace view sch1.v_1
  2  as select * from scott.emp;
as select * from scott.emp
                       *
error in line 2:
ORA-00942: table or view does npt exist


SQL> grant select on scott.emp to sch1;


SQL> create or replace view sch1.v_1
  2  as select * from scott.emp;

View created.

Answer 2

这有帮助

Oracle Create View issue

GRANT SELECT ON SCH2.TAB_A TO SCH1;

GRANT SELECT ON SCH2.TAB_B TO SCH1

GRANT SELECT ON SCH2.MY_V TO SCH1;

查询正在运行，但查看未创建

2 个答案: