Question

我有以下查询按周（周日至周六）分组，并进行必要的计算。输出显然给出了一年中的周数。作为第一步，我可以将这些数据存储在一个表中，然后当我想使用这些数据时，我想将周数转换为实际的日期范围。以下是查询。

SELECT
  DATEPART(WW,aa.Time) ddtt ,bb.Nd ,'Percentages' Report
  ,case when SUM(ZZ) = 0 then 0 else convert(decimal(18,3),SUM((CCC+PSY))*100/SUM(ZZ)) end Cond1
  ,case when SUM(ZZ) = 0 then 0 else convert(decimal(18,3),SUM(USN)*100/SUM(ZZ)) end Cond2
FROM db2000.dbo.Table aa join db2000.dbo.List bb on aa.Device = bb.DeviceID
where aa.Time between '2013/12/15' AND '2014/1/15 23:00' and Nd like '_s1'
group by bb.Nd ,DATEPART(WW,aa.Time)
order by ddtt

此查询的输出是

ddtt      Nd       Report         Cond1  Cond2
1         21S      Percentages    94.787 63.998
1         41S      Percentages    94.592 63.473
1         61S      Percentages    94.356 65.845
2         21S      Percentages    93.802 64.594
2         41S      Percentages    94.141 65.486
2         61S      Percentages    93.849 66.144
3         21S      Percentages    94.572 65.940
3         41S      Percentages    95.123 67.261
3         61S      Percentages    95.044 67.211
51        21S      Percentages    94.042 65.245
51        41S      Percentages    94.857 65.847
51        61S      Percentages    94.036 67.019
52        21S      Percentages    94.592 65.469
52        41S      Percentages    95.071 66.159
52        61S      Percentages    93.932 66.989
53        21S      Percentages    94.786 65.391
53        41S      Percentages    95.266 66.883
53        61S      Percentages    94.526 67.504

我希望列ddtt的值代表实际日期，例如。 05/01/2014 - 11/01/2014。完成此操作的单独查询也可以。

Answer 1

根据您可以使用的周数，从周日到周六获取日期

SELECT dateadd(dd, -datepart(wk, '2014-01-08') - 1
             , dateadd(ww, @weeknum, '2014-01-01'))
     , dateadd(dd, -datepart(wk, '2014-01-08') - 2
             , dateadd(ww, @weeknum + 1, '2014-01-01'))

其中@weeknum是周数，对于我使用datepart(wk, '2014-01-08')的星期几，因为无论实际的星期日如何，使用1月的第一天将始终返回1。

您的查询将变为

SELECT DATEADD(dd, -DATEPART(wk, '2014-01-08') - 1
             , DATEADD(ww, DATEPART(WW,aa.Time), '2014-01-01'))
     , DATEADD(dd, -DATEPART(wk, '2014-01-08') - 2
             , DATEADD(ww, DATEPART(WW,aa.Time) + 1, '2014-01-01'))
     , bb.Nd
     , 'Percentages' Report
     , CASE WHEN SUM(ZZ) = 0 THEN 0
            ELSE convert(decimal(18,3),SUM((CCC+PSY))*100/SUM(ZZ))
       END Cond1
     , CASE WHEN SUM(ZZ) = 0 THEN 0
            ELSE convert(decimal(18,3),SUM(USN)*100/SUM(ZZ))
       END Cond2
FROM   db2000.dbo.Table aa
       JOIN db2000.dbo.List bb ON aa.Device = bb.DeviceID
WHERE  aa.Time BETWEEN '2013/12/15' AND '2014/1/15 23:00' AND Nd LIKE '_s1'
GROUP BY bb.Nd ,DATEPART(WW,aa.Time)
ORDER BY ddtt

或类似的东西，如果你想在字符串中加入两个日期。

SQL Server 2008从一周中获取日期范围

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