Question

任务正在跟随。实现函数char * stringstat（const char * s），它将计算字符数，数字，空格字符和不可打印的字符数，并输出结果字符串，形式为：characters：w digits：x spaces：y non-print： z，其中w，x，y和z是相应的量。到目前为止，我已经收集了这些原材料。

#include <stdio.h>
#include <string.h>

using namespace std;

int main(void)
{
    char str[]="something.-21";
    int length = strlen(str);

    printf("The ASCII value of %c is %d ",character,storeAscii);
    if (storeAscii>=65 && storeAscii<=90)
    {
        printf("\nYou have entered a capital letter");
    }
    else if (storeAscii>=97 && storeAscii<=122)
    {
        printf("\nYou have entered a small letter");
    }
    else if (storeAscii>=47 && storeAscii<=57)
    {
        printf("\nYou have entered a digit ");
    }
    else if (storeAscii>=0 && storeAscii>=47
          || storeAscii>=54 && storeAscii<=64
          || storeAscii>=91 && storeAscii<=96
          || storeAscii>=123 && storeAscii<=127)
    {
        printf("\nYou have entered a special character");
    }

    return 0;
}

我知道我必须拥有＆＃34;因为＆＃34;检查字符串中的每个符号并在符号上挂起的循环添加count ++然后我可以输出数量。我真的不知道如何对字符串进行循环检查。

非常感谢timrau 与此任务相对应的最终产品是：

#include<stdio.h>
#include<string.h>
#include <cctype>
int main()
{
  char str[]="This sentence is messed up. It has 32413523.";
  int w = strlen(str);
  int x=0,y=0,z=0;

  for(char *ptr = str; *ptr!='\0';++ptr)
  {
      if(isdigit(*ptr)){x++;}
      else if(isblank(*ptr)){y++;}
      else if(isprint(*ptr)){z++;}
  }
    printf("In sentence \"%s\" there is:\n",str);
    printf("Characters: %d\n",w);
    printf("Digits: %d\n",x);
    printf("Space characters: %d\n",y);
    printf("Non-printable characters: %d\n",z);
return 0;
}

Answer 1

#include <cctype>

for (char *ptr = str; *ptr != '\0'; ++ptr)
{
    if (isupper(*ptr)) { /* upper case */ }
    else if (islower(*ptr)) { /* lower case */ }
    else if (isdigit(*ptr)) { /* decimal digit */ }
    else { /* special */ }
}

字符串统计功能

1 个答案: