PHP preg_match数组并回显匹配

Question

我发布了youtube链接。

所以我想查找所有匹配项，将其替换为自定义链接并将其回显。

**这是样本帖子：

  Life is good
 {youtube}NgBZrRCPCH8{/youtube}

 Fun is great!
 {youtube}joRCPCH8{/youtube}

 Earth is round and roll
 {youtube}pwnkfH8{/youtube}**

Youtube链接就像json：    的 {的YouTube} NgBZrRCPCH8 {/ YouTube的}

像 youtube.com/NgBZrRCPCH8

之类的东西

这是我一直在尝试的。

    $con="Life is good
     {youtube}NgBZrRCPCH8{/youtube}

     Fun is great!
     {youtube}joRCPCH8{/youtube}

     Earth is round and roll
     {youtube}pwnkfH8{/youtube}";

$pattern="/{youtube}/";

$replace="";

$first= preg_replace($pattern,$replace,$con);

$pat="{/youtube}";

$rep="";

$sec=preg_replace($pat,$rep,$first);

$patt="/{}/";

$repl="";

$last=preg_replace($patt,$repl,$sec);

if($last){echo '<div class="vid">
        <div class="vendor">
            <iframe width="300" height="200" src="http://www.youtube.com/embed/'.$last.'" frameborder="0" allowfullscreen></iframe>
          </div>

      </div>';}

感谢...

Answer 1

我不确定你要做什么，但根据我的理解，我做了这个

$re = '/{youtube}(.*){\/youtube}/m'; 
$str="Life is good
     {youtube}NgBZrRCPCH8{/youtube}

     Fun is great!
     {youtube}joRCPCH8{/youtube}

     Earth is round and roll
     {youtube}pwnkfH8{/youtube}";

preg_match_all($re, $str, $matches);

$re = '/([\w ]+)[^a-zA-Z {}]+(?!{)/m'; 

preg_match_all($re, $str, $matches1);

echo '<div class="vid">';
foreach ($matches[1] as $key => $value) {
    echo '<div class="vendor">
    '.$matches1[0][$key].'
            <iframe width="300" height="200" src="http://www.youtube.com/embed/'.$value.'" frameborder="0" allowfullscreen></iframe>
          </div>';
}
echo '</div>';

<强> 输出

Answer 2

另一种方式：

$trans = array ('{youtube}'  => '<iframe width="300" height="200" src="http://www.youtube.com/embed/',
                '{/youtube}' => '" frameborder="0" allowfullscreen></iframe></div><div class="vendor">');

$result = '<div class="vid"><div class="vendor">'
        . substr(strtr($str, $trans), 0, -20) . '</div>';