Question

我正在尝试将值发布到服务器身份验证方法http：// * / Token。从我的C＃客户端我得到400错误请求错误。虽然它在jquery中运行良好。

jQuery代码：

$( "#post2").click(function() {
    var Email=$('#Email').val();
    var Password=$('#Password').val();
    $.ajax({
        type:"Post",                    
        url: "http://***/Token",
        data:{
                "grant_type": "password",
                "username": Email,
                "password": Password
            },
        success: function(msg) 
        {
            user=msg["access_token"];
            console.log(JSON.stringify(msg));
        }
    });
});

C＃代码

string email = "***@gmail.com";
string password = "***";
var tok = new TokenModel{grant_type = "password", username = email, password = password};
var s = JsonConvert.SerializeObject (tok);

var request = HttpWebRequest.Create (string.Format (@"http://***/Token", ""));
request.ContentType = "application/json";
request.Method = "POST";
using (var writer = new StreamWriter (request.GetRequestStream ())) {
    writer.Write (s);
}

using (HttpWebResponse responses = request.GetResponse () as HttpWebResponse) {

}

我也尝试过创建本地json

var x = new
{
    grant_type = "password",
    username = "****@gmail.com",
    password = "***"
};

但仍然是同样的错误。

从C＃客户端调用服务器有什么我应该做的额外工作吗？

请帮忙，感谢

Answer 1

jQuery的ajax()的{{1}}参数不包含json对象，而是一个后来被转换为post参数的对象（例如data）。

所以试试：

?var1=foo&var2=bar

Answer 2

解决：

    public async Task<string> Login(string username, string password)
    {

        HttpWebRequest request = new HttpWebRequest(new Uri(String.Format("{0}Token", "http://***.net/")));
        request.Method = "POST";

        string postString = String.Format("username={0}&password={1}&grant_type=password", HttpUtility.HtmlEncode(username), HttpUtility.HtmlEncode(password));
        byte[] bytes = Encoding.UTF8.GetBytes(postString);
        using (Stream requestStream = await request.GetRequestStreamAsync())
        {
            requestStream.Write(bytes, 0, bytes.Length);
        }

        try
        {
            HttpWebResponse httpResponse =  (HttpWebResponse)(await request.GetResponseAsync());
            string json;
            using (Stream responseStream = httpResponse.GetResponseStream())
            {
                json = new StreamReader(responseStream).ReadToEnd();
                Console.WriteLine(json);
            }
            TokenResponseModel tokenResponse = JsonConvert.DeserializeObject<TokenResponseModel>(json);
            return tokenResponse.AccessToken;
        }
        catch (Exception ex)
        {
            Console.WriteLine ("h..........." + ex);
            //throw new SecurityException("Bad ls", ex);
            return null;
        }
    }

400错误请求：C＃

2 个答案: