我使用Djrill从我的Django应用程序发送电子邮件。
使用ajax,我按如下方式调用处理电子邮件发送的视图:
$.ajax({
url: "/sendmail&name="+name+"&receiver="+email+"&phone="+phone+"&address="+address,
type: 'GET',
success: function(){
console.log('done');
}
});
views.py就是:
def sendEmail(request):
if 'receiver' in request.GET and request.GET['receiver']:
name = request.GET['name']
recv = request.GET['receiver']
phone = request.GET['phone']
address = request.GET['address']
from django.core.mail import send_mail
send_mail("Service name: "+name, "Phone Number: "+phone+" <br>Address: "+address, "<sender@example.com", [recv])
return 'True Data'
else:
return 'False data'
Urls.py
url(r'^sendmail$', views.sendEmail, name='sendmail'),
对ajax调用的响应给出了404错误。
知道这里发生了什么吗?
答案 0 :(得分:4)
请求中的网址应为sendmail?
而不是sendmail&
:
url: "/sendmail?name="+name+"&receiver="+email+"&phone="+phone+"&address="+address,
^ there
否则,它正在寻找一个格式为sendmail&name=(.+)
的网址,显然不存在。
有关详细信息,请参阅Query string structure(但我认为这也是您的错字)