我正在实施find the nearest location
(机场,酒店等)。我已经实现了一些代码,并在Google Place API
上注册了我的应用程序。
我收到了一个错误。我已经将我的代码放在这里,并使用了我使用的API密钥的屏幕截图。
{
Bitmap bitmap = BitmapFactory.decodeResource(getResources(), R.drawable.ic_launcher);
CameraPosition cameraPosition = new CameraPosition.Builder().target(
new LatLng(latitude,longitude)).zoom(18).build();
googleMap.setMapType(GoogleMap.MAP_TYPE_NORMAL);
googleMap.animateCamera(CameraUpdateFactory.newCameraPosition(cameraPosition));
marker = new MarkerOptions().position(new LatLng(latitude, longitude));
googleMap.addMarker(marker.draggable(true));
googleMap.setIndoorEnabled(true);
StringBuilder sb = new StringBuilder("https://maps.googleapis.com/maps/api/geocode/json?");
sb.append("location="+latitude+","+longitude);
sb.append("&radius=5000");
sb.append("&types="+"Mosque");
sb.append("&sensor=true");
sb.append("&key=apikey is shown in image below");
System.out.println("url :-" + sb.toString());
PlacesTask placesTask = new PlacesTask();
placesTask.execute(sb.toString());
}
private class PlacesTask extends AsyncTask<String, Integer, String>{
String data = null;
@Override
protected String doInBackground(String... url) {
try{
data = downloadUrl(url[0]);
}catch(Exception e){
Log.d("Background Task",e.toString());
}
return data;
}
@Override
protected void onPostExecute(String result){
System.out.println("Data :- " + data);
}
}
/** A method to download json data from url */
private String downloadUrl(String strUrl) throws IOException{
String data = "";
InputStream iStream = null;
HttpURLConnection urlConnection = null;
try{
URL url = new URL(strUrl);
urlConnection = (HttpURLConnection) url.openConnection();
urlConnection.connect();
iStream = urlConnection.getInputStream();
BufferedReader br = new BufferedReader(new InputStreamReader(iStream));
StringBuffer sb = new StringBuffer();
String line = "";
while( ( line = br.readLine()) != null){
sb.append(line);
}
data = sb.toString();
br.close();
}catch(Exception e){
Log.d("Exception while downloading url", e.toString());
}finally{
iStream.close();
urlConnection.disconnect();
}
return data;
}
API控制台
错误
{&#34; error_message&#34; :&#34;此API项目无权使用此API。&#34;,&#34;结果&#34; :[],&#34;状态&#34; :&#34; REQUEST_DENIED&#34;}
答案 0 :(得分:0)
试试这个。
LocationManager lm = (LocationManager) getApplicationContext()
.getSystemService(Context.LOCATION_SERVICE);
Location net_loc = null;
lm.getLastKnownLocation(LocationManager.GPS_PROVIDER);
您可以从net_loc获取当前位置。