Question

我有2个xml文件

MainActivity.xml 2.Example.xml

我在Example.xml中有listview。我在Example.java中编写的代码。但是数据没有显示在listview中。请仔细阅读我的代码

的example.xml

<?xml version="1.0" encoding="utf-8"?>
<ViewSwitcher xmlns:android="http://schemas.android.com/apk/res/android"
    android:id="@+id/profileSwitcher"
    android:layout_width="fill_parent"
    android:layout_height="fill_parent">

<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    android:orientation="vertical" >

    <ListView
        android:id="@+id/listPasscode"
        android:layout_height="wrap_content"
        android:layout_width="match_parent">
    </ListView>
    <TextView
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:text="Test"/>


</LinearLayout>
    </ViewSwitcher>

Example.java

public class ListViewAndroidExample extends Activity {
    ListView listView ;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);


        listView = (ListView) findViewById(R.id.listPasscode);

        // Define a new Adapter
        // First parameter - Context
        // Second parameter - Layout for the row
        // Third parameter - ID of the TextView to which the data is written
        // Forth - the Array of data

        // Array of strings...
        String[] countryArray = {"India", "Pakistan", "USA", "UK"};

        ArrayAdapter<String> adapter = new ArrayAdapter<String>(this,
          android.R.layout.simple_list_item_1, android.R.id.text1, countryArray);

        // Assign adapter to ListView
        listView.setAdapter(adapter);

        setContentView(R.layout.activity_list_view_android_example);

    }

}

xml和java文件之间是否正确链接？如果不建议我

Answer 1

试试这个..

在初始化setContentView

之前添加ListView

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);

    setContentView(R.layout.activity_list_view_android_example);
    listView = (ListView) findViewById(R.id.listPasscode);

修改

改变这个..

ArrayAdapter<String> adapter = new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, android.R.id.text1, countryArray);

到

ArrayAdapter<String> adapter = new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, countryArray);

如何在android中的xml文件中显示listview内容

1 个答案: