Question

我有这段代码：

<?php
mysql_connect('localhost', 'sql', 'abc123');
mysql_select_db('common');
$phone_mobile = mysql_real_escape_string($_POST['phone_mobile']);
$result = mysql_query('SELECT phone_mobile FROM leads WHERE phone_mobile = "'.$phone_mobile.'"');
if(mysql_num_rows($result)>0){
echo 1;
} else {
echo 0;
}
?>

这有效;但是我在表格中有相同的列＃34;联系人＆＃34;。

因此我需要查询相同列名（phone_mobile）的表（线索）和表格（联系人）。

如果phone_mobile位于＆＃34;引导＆＃34;或＆＃34;联系人＆＃34;或两者都回显结果。

我假设UNION或JOIN查询正在进行中？

提前完成。

约翰

Answer 1

你可以使用UNION

$result = mysql_query('  SELECT phone_mobile FROM (
  SELECT phone_mobile FROM leads WHERE phone_mobile = "'.$phone_mobile.'"
  UNION
  SELECT phone_mobile FROM contacts WHERE phone_mobile = "'.$phone_mobile.'"
   )t
  GROUP BY phone_mobile ') ;

Answer 2

将contacts添加到您的查询

mysql_query("SELECT phone_mobile FROM leads, contacts WHERE phone_mobile = "'.$phone_mobile.'");

一般来说：

SELECET 'Column 1'[,'Column 2','Column 3', ...]
FROM 'Table1', [,'Table 2','Table 3', ...]
WHERE 'Condition 1' [AND 'Condition 2' AND 'Column 3', ...]

如果您的'phone_mobile'列在2个或更多表中的名称不同，请使用以下语法：

SELECT Table1.phone_number_t1, Table2.phone_number_t2

而

SELECT phone_mobile FROM Table1, Table2

AND Condtions将

WHERE Table1.phone_mobile =“'。$ phone_mobile。'”或Table2.phone_mobile =“'。$ phone_mobile。'”

而

WHERE phone_mobile =“'。$ phone_mobile。'”

Answer 3

你可以

 SELECT l.phone_mobile, c.phone_mobile FROM leads l, contacts c WHERE l.phone_mobile = '$phone_mobile' OR c.phone_mobile = '$phone_mobile';

然后检查两个字段是否包含值。

Answer 4

您只需写下面的查询

$query = "select phone_mobile from leads,contacts where leads.phone_mobile = '".$phone_mobile."'";

$result = mysql_query($query) or die("Mysql error says : ".mysql_error());
if(mysql_num_rows($result)>0){
  echo 1;
} else {
  echo 0; 
}

Answer 5

尝试使用COALESCE，

SELECT COALESCE(l.phone_mobile,c.phone_mobile) mobilePhone  FROM leads l,
contacts c 
WHERE l.phone_mobile='".$phone_mobile."'

如何查询Mysql多个表

5 个答案: