Question

我有一张名为＆＃34;维护＆＃34;和另一个＆＃34;进程＆＃34;和＆＃34;汽车＆＃34;。的维护：

id   car_id   process_id   date
1     1        1           4/26/2013
2     1        1           5/26/2013
3     1        2           5/26/2013

我想根据最大日期为car_id和process_id重复选择不同的值。所以我想：

id   car_id   process_id   date
2    1          1          5/26/2013
3    1          1          5/26/2013

我有这个：

SELECT m.*, u.username, c.milage, p.*, s.name
                                    FROM maintenances as m
                                         LEFT JOIN users AS u
                                         ON u.id = m.user_id 
                                         LEFT JOIN cars AS c
                                         ON c.id = m.car_id
                                         LEFT JOIN processes as p
                                         ON p.id = m.process_id
                                         LEFT JOIN services as s
                                         ON s.id = m.service_id
                                    Group by m.car_id, m.process_id

但是这给了我：

id   car_id   process_id   date
 1    1          1          4/26/2013
 3    1          2          5/26/2013

我想：

 id   car_id   process_id   date
  2    1          1          5/26/2013
  3    1          2          5/26/2013

Answer 1

尝试将maintenances加入带有MAX(date)的子查询：

  SELECT m.*, u.username, c.milage, p.*, s.name
  FROM maintenances as m
  JOIN 
      (SELECT car_id, process_id, MAX(date) as MAX_DATE 
       FROM maintenances  
       GROUP BY by car_id, process_id) as MAX_T ON m.car_id = MAX_T.car_id 
                    AND m.process_id = MAX_T.process_id 
                    AND m.date = MAX_T.MAX_DATE
  LEFT JOIN users AS u ON u.id = m.user_id 
  LEFT JOIN cars AS c ON c.id = m.car_id
  LEFT JOIN processes AS p ON p.id = m.process_id
  LEFT JOIN services AS s ON s.id = m.service_id

选择不同的最大日期

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