Question

我想通过用下划线替换所有包含空格的pdf文件。所以我调用命令：

ls *.pdf | sed -e 'p; s/" "/_/' | xargs -n2 mv

我在终端上遇到错误：

mv: cannot stat ‘Beginning’: No such file or directory
mv: cannot stat ‘Linux’: No such file or directory
mv: cannot stat ‘Line.pdf’: No such file or directory
mv: cannot stat ‘The’: No such file or directory
mv: cannot stat ‘Command’: No such file or directory
mv: cannot stat ‘Head’: No such file or directory
mv: cannot stat ‘C.pdf’: No such file or directory
mv: cannot stat ‘First’: No such file or directory
mv: cannot stat ‘Head’: No such file or directory
mv: cannot stat ‘PHP’: No such file or directory
mv: cannot stat ‘MySQL.pdf’: No such file or directory
mv: cannot stat ‘First’: No such file or directory
mv: cannot stat ‘and’: No such file or directory
mv: cannot stat ‘Linux’: No such file or directory
mv: cannot stat ‘Guide.pdf’: No such file or directory
mv: cannot stat ‘Pocket’: No such file or directory
mv: cannot stat ‘The’: No such file or directory
mv: cannot stat ‘C.pdf’: No such file or directory
mv: cannot stat ‘ANSI’: No such file or directory
mv: cannot stat ‘The’: No such file or directory
mv: cannot stat ‘Command’: No such file or directory
mv: cannot stat ‘The’: No such file or directory
mv: cannot stat ‘Command’: No such file or directory
mv: cannot stat ‘The’: No such file or directory
mv: cannot stat ‘Programming’: No such file or directory
mv: cannot stat ‘The’: No such file or directory
mv: cannot stat ‘Programming’: No such file or directory

那么命令有什么问题？

Answer 1

获取基于Perl的rename命令（有时称为prename）来完成这项工作：

prename 's/ /_/g' *.pdf

shell globbing将每个文件名分开; prename命令执行批量重命名; s/ /_/g操作将文件名中的每个空格替换为_。（原始代码仅用下划线替换第一个空白，然后在空格（空格和制表符以及换行符）上违反xargs错误。

Answer 2

您可以尝试引用文件名：

ls *.pdf | sed -e 's/.*/"&"/; p; s/ /_/g' | xargs -n2 mv

这可能也是你手工操作的方式：

mv "File with spaces" "File_with_spaces"

依靠纯粹的bash，你必须使用for-loop和bash替换：

for file in $(ls *.pdf); do echo "$file" "${file// /_}"; done

Answer 3

首先，您的sed命令与任何文件都不匹配，因为您尝试匹配quote-space-quote而不仅仅是space。除非您的文件名为A" "file.pdf，否则您将无法与sed匹配。

我们假设您已将其修复为sed -e 'p; 's/ /_/g'。如果您有一个名为A file.pdf的文件，则输出将为

A file.pdf
A_file.pdf

并将这些作为参数传递给xargs。但是，xargs被指示采用前两个参数。在这种情况下，它们将是A和file.pdf，两者都不存在，因此mv无法统计它们！

在我看来，这是一种更简单的方法：

for file in *.pdf; do mv "$file" "$(echo $file | sed 's/ /_/g')"; done

如何在包含空格的Linux中批量重命名文件？

3 个答案: