Question

为了轻松导入数据库数据，我尝试编写一些PHP代码以帮助我。我有2个数组，＆＃34; list＆＃34;这是常规的aray。其他＆＃34; order1＆＃34;是一个关联数组。我试图比较第一个值和第二个键来制作我需要的列表..像多重查找和替换...

array：list

[0] => Apple 
[1] => Apple 
[2] => Apple 
[3] => Apple 
[4] => Bannana 
[5] => Mango 
[6] => Mango 
[7] => Mango 
[8] => Mango 
[9] => Mango 
[10] => Pear 
[11] => Pear 
[12] => Pear 
[13] => Pear 
[14] => Pineaple 
[15] => Strawberry 
[16] => Strawberry 
[17] => Watermelon 
[18] => Watermelon 
[19] => Watermelon 
[20] => Watermelon

数组：order1

[Apple] => 1
[Bannana] => 2
[Mango] => 3
[Pear] => 4
[Pineaple] => 5
[Strawberry] => 6
[Watermelon] => 7

我想得到：

但是...

$final=array();
foreach($list as $keyl => $valuel){
   foreach($order1 as $keyo => $valueo){
      if($valuel==$keyo) {
        $final[].=$valueo;
      }
   }
}
print_r($final);

让我只有7，最后一个元素..

var的递归/生命有什么问题吗？但我似乎无法得到它..

Answer 1

因为您感兴趣的部分是＆＃34;值＆＃34; $order1具有您已知道的索引，您不会需要内循环，而只需使用isset()来验证索引是否存在，如果存在，则参考直接。

例如：

$final = array();
foreach ($list as $index => $key_name) {
    if (isset($order1[$key_name])) {
        $final[] = $order1[$key_name];
    }
}

print_r($final);

Codepad Example

Answer 2

我认为您在数组初始化时搞砸了，因为下面的代码按预期工作（根据我的理解）

$list = ["Apple", "Apple", "Apple", "Apple", "Bannana", "Mango", "Mango", "Mango", "Mango", "Mango", "Pear", "Pear", "Pear", "Pear", "Pineaple", "Strawberry", "Strawberry", "Watermelon", "Watermelon", "Watermelon", "Watermelon"];
$order1 = [
  "Apple" => 1,
  "Bannana" => 2,
  "Mango" => 3,
  "Pear" => 4,
  "Pineaple" => 5,
  "Strawberry" => 6,
  "Watermelon" => 7
];
$final=array();
foreach($list as $keyl => $valuel){
   foreach($order1 as $keyo => $valueo){
      if($valuel==$keyo) {
        $final[].=$valueo;
      }
   }
}    
print_r($final)

PHP比较一个值和另一个数组的键

2 个答案: