Question

我尝试在set-acl cmdlet中使用我的函数，但它确实正常工作，我的函数被识别为一个简单的＆＃34;字符串＆＃34;。

$acl = Get-Acl C:\MSI -Verbose
$acl.SetAccessRuleProtection($True, $False) 
$rule = New-Object System.Security.AccessControl.FileSystemAccessRule ("Get-GroupName -SID 'S-1-1-0'","FullControl", "ContainerInherit, ObjectInherit", "None", "Allow") -Verbose 
$acl.AddAccessRule($rule) 
$rule = New-ObjectSystem.Security.AccessControl.FileSystemAccessRule("Get-GroupName -SID 'S-1-5-32-544'","Readandexecute", "ContainerInherit, ObjectInherit", "None", "Allow") -Verbose 
$acl.AddAccessRule($rule) 
Set-Acl C:\MSI $acl

Answer 1

它被识别为一个字符串，因为你把它写成一个字符串。引号内的所有内容（＆＃34;或＆＃39;）都是字符串。

如果你的函数返回一个字符串值，那么你可以像这样使用它：

$acl = Get-Acl C:\MSI -Verbose
$acl.SetAccessRuleProtection($True, $False) 
$rule = New-Object System.Security.AccessControl.FileSystemAccessRule ((Get-GroupName -SID 'S-1-1-0'),"FullControl", "ContainerInherit, ObjectInherit", "None", "Allow") -Verbose 
$acl.AddAccessRule($rule) 
$rule = New-ObjectSystem.Security.AccessControl.FileSystemAccessRule((Get-GroupName -SID 'S-1-5-32-544'),"Readandexecute", "ContainerInherit, ObjectInherit", "None", "Allow") -Verbose 
$acl.AddAccessRule($rule) 
Set-Acl C:\MSI $acl

cmdlet中的函数名称

1 个答案: