PHP函数应该返回我的数组，但只返回一个来自mysql表的结果

Question

我希望我的日历显示来自mysql表的所有事件，但是这段代码只显示了最后一个。这是我的代码：

$result5 = mysqli_query($con,"SELECT * FROM event WHERE username IN  ('$matches')");
$num_rows = mysqli_num_rows($result5);

    while($row5 = mysqli_fetch_array($result5)) 
            {

            $time=strtotime($row5['start_date']);
            $day = date("d",$time);
            $month= date("m",$time);
            $month2= date("F",$time);
            $year=date("Y",$time);


            echo "$day $month $year ".$row5['name_event'] ; // this show me correct
            echo '<br/>';

            $calendar = new donatj\SimpleCalendar();

            $calendar->addDailyHtml( "Event", "$day-$month-$year");// there is some problem
            }
            $calendar->show(true);

我使用的函数中有代码：

public function addDailyHtml( $html, $start_date_string, $end_date_string = null ) {
    static $htmlCount = 0;
    $start_date = strtotime($start_date_string);
    if( $end_date_string ) {
        $end_date = strtotime($end_date_string);
    } else {
        $end_date = $start_date;
    }

    $working_date = $start_date;
    do {
        $tDate = getdate($working_date);
        $working_date += 86400;
        $this->daily_html[$tDate['year']][$tDate['mon']][$tDate['mday']][$htmlCount] = $html;
    } while( $working_date < $end_date + 1 );

    $htmlCount++;

}

有人可以帮助我，为什么日历只显示一个事件？