Question

我有两个字符串列表，我想用它们来创建一个字符串列表。

m1 = ["Ag", "Pt"]
m2 = ["Ir", "Mn"]
codes = []
for i in range (len (m1) ):
    codes.append('6%s@32%s' %(m1[i], m2[i] ) )
print codes

例如代码可以包含[＆＃34; 6Ag @ 32Ir＆＃34;，＆＃34; 6Pt @ 32Mn＆＃34;]

我想将以下内容转换为列表理解。

Answer 1

非拉链方法：

>>> m1 = ["Ag", "Pt"]
>>> m2 = ["Ir", "Mn"]
>>> ['6%s@32%s' %(m1[i], m2[i]) for i in range(min(len(m1), len(m2)))]
['6Ag@32Ir', '6Pt@32Mn']

将其变成发电机：

>>> ('6%s@32%s' %(m1[i], m2[i]) for i in xrange(min(len(m1), len(m2))))

Python 2，你可以这样做：

>>> ['6%s@32%s' % (x, y) for x, y in map(None, m1, m2)]
['6Ag@32Ir', '6Pt@32Mn']

或者，您甚至不需要解压缩元组：

>>> ['6%s@32%s' % t for t in map(None, m1, m2)]

Answer 2

你可以简单地zip他们并按照这样打印

m1, m2 = ["Ag", "Pt"], ["Ir", "Mn"]
print ["6{}@32{}".format(*items) for items in zip(m1, m2)]
# ['6Ag@32Ir', '6Pt@32Mn']

或者，如果您更喜欢map方法，

from itertools import starmap
print list(starmap("6{}@32{}".format, zip(m1, m2)))

或者

print [item for item in starmap("6{}@32{}".format, zip(m1, m2))]

Answer 3

您可以使用list comprehension和zip：

>>> m1 = ["Ag", "Pt"]
>>> m2 = ["Ir", "Mn"]
>>> zip(m1, m2)  #  zip is used to pair-up the items in m1 and m2
[('Ag', 'Ir'), ('Pt', 'Mn')]
>>> ["6%s@32%s" % x for x in zip(m1, m2)]
['6Ag@32Ir', '6Pt@32Mn']
>>>

请注意，如果m1和m2可能很大，则应使用itertools.izip而不是zip（在Python 2.x中创建不必要的列表）。但是，您的示例中的列表足够小，这不是问题。

列表理解以从两个列表创建字符串列表

3 个答案: