Java已排序和可迭代的Defaultlistmodel

时间:2014-05-24 18:34:10

标签: java swing sorting jlist defaultlistmodel

我正在尝试扩展DefaultListModel,以便它可以进行排序和迭代。我在这里找到了一些代码http://www.javalobby.org/java/forums/t94074.html。我现在正在尝试参数化此代码,但addAll,containsAll,removeAll,retainAll和toArray方法都会给出名称冲突错误。我有点理解为什么会这样,但我不确定如何解决它。有一个更好的方法吗?代码

package main;

import javax.swing.DefaultListModel;

import javax.swing.*;
import java.util.*;

public class DefaultListModelSort<E extends Object> extends DefaultListModel<E>
        implements List<E> {
    private Delegate m_delegate = new Delegate();

    public DefaultListModelSort() {
        super();
    }

    public DefaultListModelSort(Collection<E> c) {
        this();
        addAll(c);
    }

    public boolean add(E o) {
        return m_delegate.add(o);
    }

    public boolean removeE(E o) {
        return m_delegate.remove(o);
    }

    public boolean addAll(int index, Collection<E> c) {
        return m_delegate.addAll(index, c);
    }

    public boolean addAll(Collection<E> c) {
        return m_delegate.addAll(c);
    }

    public boolean containsAll(Collection<E> c) {
        return m_delegate.containsAll(c);
    }

    public boolean removeAll(Collection<E> c) {
        return m_delegate.removeAll(c);
    }

    public boolean retainAll(Collection<E> c) {
        return m_delegate.retainAll(c);
    }

    public Iterator<E> iterator() {
        return m_delegate.iterator();
    }

    public List<E> subList(int fromIndex, int toIndex) {
        return m_delegate.subList(fromIndex, toIndex);
    }

    public ListIterator<E> listIterator() {
        return m_delegate.listIterator();
    }

    public ListIterator<E> listIterator(int index) {
        return m_delegate.listIterator(index);
    }

    public E[] toArray(E a[]) {
        return m_delegate.toArray(a);
    }

    /**
     * This class extends AbstractList so we get all the functionality of
     * iterators and such for free.
     */
    private class Delegate extends AbstractList<E> {

        public Delegate() {
            super();
        }

        public E get(int index) {
            return DefaultListModelSort.super.get(index);
        }

        public int size() {
            return DefaultListModelSort.super.size();
        }

        public E set(int index, E element) {
            return DefaultListModelSort.super.set(index, element);
        }

        public void add(int index, E element) {
            DefaultListModelSort.super.add(index, element);
        }

        public E remove(int index) {
            return DefaultListModelSort.super.remove(index);
        }
    }
}

1 个答案:

答案 0 :(得分:3)

  

我试图扩展DefaultListModel,以便它可以排序   可迭代。