Question

这是我的模特：

function item_attributes_data($id){
    $query=$this->db->query("SELECT       attributes.attribute_text,item_attributes.attr_value,item_attributes.cost
    FROM attributes
    INNER JOIN item_attributes
    ON attributes.id=item_attributes.attr_id
    where item_attributes.item_id=".$id);

    return $query->result();
}

这是我的控制器：

function item_attributes()
{
    header('Access-Control-Allow-Origin:*');
    $id=$this->uri->segment(3);
    $this->load->model('orderapp_model');
    $query_result=$this->orderapp_model->item_attributes_data($id);
    echo json_encode($query_result);
}

我将数据检索为

url=localhost/ordertakeadmin/index.php/orderapp/item_attributes/

我得到了JSON数组如下：

options = [{
    "attribute_text": "VEHICLE",
    "attr_value": "Truck",
    "cost": "897.00"
}, {
    "attribute_text": "MATERIAL",
    "attr_value": "Steel",
    "cost": "385.00"
}, {
    "attribute_text": "SIZE",
    "attr_value": "Medium",
    "cost": "254.00"
}]

但我想将数据构建为

options = [{
    attribute_text: "SIZE",
    choices: [{
        attr_value: "Medium",
        cost: 254.00
    }, {
        attr_value: "Small",
        cost: 154.00
    }, {
        attr_value: "Large",
        cost: 280.00
    }]
}, {
    attribute_text: "MATERIAL",
    choices: [{
        attr_value: "Steel",
        cost: 385.00
    }, {
        attr_value: "Carbon Fiber",
        cost: 285.00
    }, ]
}, {
    attribute_text: "VEHICLE",
    choices: [{
        attr_value: "Truck",
        cost: 897.00
    }, {
        attr_value: "Car",
        cost: 122.00
    }]
}];

这是我的数据库： attribute_text attr_value成本
尺寸大1500.00 VEHICLE Truck 897.00 材料钢385.00 SIZE Medium 254.00 VEHICLE Car 855.00 VEHICLE吉普车875.00 材料铅897.00

怎么可能？

Answer 1

我试过破译你的问题，我想你想要这样的事情：

function item_attributes_data($id){
    // first get your attributes
    $query=$this->db->query("SELECT id, attributes.attribute_text FROM attributes");

    $attributes = $query->result();

    $finalResult = array();

    // then get the items for each attribute
    foreach($attributes as $attribute) {
        // fetch the items
        $itemsQuery = $this->db->query("SELECT attr_value, cost FROM item_attributes WHERE attr_id=" . $attribute['id']);

        $items = $itemsQuery->result();

        $finalResult[] = array( "attribute_text" => $attribute["attribute_text"], "choices" => $items );
    }

    return $finalResult;
}

如何在PHP中的数组中构建数组

1 个答案: