Question

我只是想创建一个简短的java程序来向用户请求一个int，然后将3添加到该int并显示它。出于某种原因，我的语法都错了。

import java.util.Scanner;

public class test {


    public int attempt (int b) {
            return 3+entry;
    }


    int r = attempt(entry);

    public static void main (String[] args){
            Scanner keyboard = new Scanner(System.in);

            System.out.println ("Enter single digit int ");
            int entry = keyboard.nextInt();


            System.out.println("Your number is " + entry);
            System.out.println("Your number is " );

            System.out.println("The final result is " + r);

            }


}

Answer 1

import java.util.Scanner;

public class test {


// this function should be static
public static int attempt (int b) {
        //b for entry, since b is the name of the variable
        return 3 + b;
}


public static void main (String[] args){
        Scanner keyboard = new Scanner(System.in);

        System.out.println ("Enter single digit int ");
        int entry = keyboard.nextInt();

        //put this in your main function
        int r = attempt(entry);
        System.out.println("Your number is " + entry);
        System.out.println("Your number is " );

        System.out.println("The final result is " + r);

        }
}

我认为你应该通过一些java教程......

Answer 2

您无法调用非静态函数或从静态函数引用非静态变量。

所以基本上你必须写

public static int attempt ....
static int r = ...

问题是静态方法在类测试上运行，而非静态方法在类测试的实例上运行。

方法中的参数未编译

2 个答案: