Question

我无法确定如何存储用户输入的操作员。我认为我的第36行是导致我的问题的原因但不确定会发生什么（我确信你可以从代码中看到但我不能;））我是否进入第35行并将操作用于整数和命中输入没有任何反应我然后键入输入任何2个字母数字字符然后输入2个字母数字然后输入然后它吐出我的答案。我知道它可能很容易让我失踪。

此外，在我使该部分工作后，我想为用户添加“do while”循环以继续使用选择的运算符，直到iValue1！= 0

最后，使用“if”cin.fail阻止用户除以0的最简单方法是什么？如果是这样，我的第一个“如果”声明会出现吗？

*编辑：第35行=“cout＆lt;＆lt;”输入您要执行的操作：“

#include <iostream>
using namespace std;

int main()
{
    float iValue1, iValue2, iValue3;

    char chOperator1 = '/';     //Initializing operators
    char chOperator2 = '*';
    char chOperator3 = '+';
    char chOperator4 = '-';

    //Get user inputs
    cout  << "Enter the first value as an integer: ";
    cin   >> iValue1;
    cout  << "Enter the Second value as an integer: ";
    cin   >> iValue2;
    cout  << "Enter the operation you want to perform: ";
    cin   >> chOperator1 >> chOperator2 >> chOperator3 >> chOperator4;


    if( chOperator1 == '/')
    {
        iValue3 = iValue1 / iValue2;
    }
    else {
        if(chOperator2 == '*')
        iValue3 = iValue1 * iValue2;
        (chOperator3 == '+');
        iValue3 = iValue1 + iValue2;
        (chOperator4 == '-');
        iValue3 = iValue1 - iValue2;
    }

    cout  << "The result is \n " << iValue3;    
    return 0;
}

Answer 1

我建议您使用数组或std :: vector进行多项操作：

char operations[4];
cout >> "Enter 4 operations: ";  
for (unsigned int i = 0; i < 4; ++i)
{
  cin >> operation[i];
}

for (unsigned int j = 0; j < 4; ++j)
{
  const char opr = operation[j];
  switch (j)
  {
    case '*':
      cout << (iValue1 * iValue2) << "\n";
      break;
    case '/':
      cout << (iValue1 / iValue2) << "\n";
      break;
    case '+':
      cout << (iValue1 + iValue2) << "\n";
      break;
    case '-':
      cout << (iValue1 - iValue2) << "\n";
      break;
    default:
      cout << "Invalid operation, '" << oper << "'\n";
      break;
    }
  }

简单的反向波兰计算器

1 个答案: