如何找到两个数字MYSQL的绝对差异

Question

在MYSQL中查找两个数字之间的绝对差异的最佳方法是什么，以便我可以订购结果？以下情况适用，仅当numberA大于numberB时，但正如您所看到的情况并非总是如此。有一个好的方法可以用一个语句来做到这一点吗？

SELECT (numberA - numberB) AS spread 
FROM table 
ORDER BY spread DESC

|-------------------|
| numberA | numberB |
| 5.4     | 2.2     |
| 7.7     | 4.3     |
| 1       | 6.5     |
| 2.3     | 10.8    |
| 4.5     | 4.5     |

Answer 1

就像that一样简单：

SELECT ABS(numberA - numberB) AS spread 
FROM table 
ORDER BY spread DESC

或者，如果你想要select the pair (numberA, numberB) in descending order of their difference：

SELECT numberA, numberB
FROM table 
ORDER BY ABS(numberA - numberB) DESC

Answer 2

MySQL具有ABS()功能：

select abs(numberA - numberB) as abs_diff
from your_table
ORDER BY abs_diff DESC