django - 如何通过日志记录筛选出GET静态和媒体消息?

时间:2014-05-23 15:54:30

标签: django logging

我正在处理一个包含大量图像的页面,因此这会在此类型的控制台中生成大量输出。在我的开发环境中,我使用django来提供静态和媒体服务,所以我在我的控制台中得到了很多这样的信息:

...
[23/May/2014 12:41:54] "GET /static/css/style.css HTTP/1.1" 304 0
[23/May/2014 12:41:55] "GET /static/js/jquery-1.7.1.min.js HTTP/1.1" 304 0
[23/May/2014 12:41:55] "GET /static/js/jquery.form.js HTTP/1.1" 304 0
...
[23/May/2014 12:41:57] "GET /media/producto/Tapa_Santiago_Vazquez_SV.jpg HTTP/1.1" 304 0
[23/May/2014 12:41:57] "GET /media/CACHE/images/producto/Barcos_y_mariposas_DVD_baja/2e3e3894ca08f88c03459e00f9018427.jpg HTTP/1.1" 304 0
[23/May/2014 12:41:56] "GET /media/CACHE/images/producto/tapaDEJA_VU/fb67e92ffd47808a263db02ca016bc24.jpg HTTP/1.1" 304 0
...

寻找有意义的输出非常繁琐。

我想在我的环境中过滤掉那些消息,所以我只看到了视图和输出的GET,但到目前为止我看到的日志记录我可能会影响来自django的其他日志记录但不是这个。我甚至试过这个,但它不起作用:

LOGGING = {
    'version': 1,
    'disable_existing_loggers': True,
    'handlers': {
        'null': {
            'level': 'ERROR',
            'class': 'django.utils.log.NullHandler',
        },
    },
    'loggers': {
        'django': {
            'handlers': ['null'],
            'level': 'ERROR',
            'propagate': True,
        },
    }
}

甚至可以过滤掉那种输出吗?

谢谢!

4 个答案:

答案 0 :(得分:13)

Django的最新版本可以很容易地使用您自己的LOGGING设置覆盖默认日志记录。

要过滤掉/static/目录的所有GET请求,请将以下内容添加到settings.py

def skip_static_requests(record):
    if record.args[0].startswith('GET /static/'):  # filter whatever you want
        return False
    return True

LOGGING = {
    'version': 1,
    'disable_existing_loggers': False,
    'filters': {
        # use Django's built in CallbackFilter to point to your filter 
        'skip_static_requests': {
            '()': 'django.utils.log.CallbackFilter',
            'callback': skip_static_requests
        }
    },
    'formatters': {
        # django's default formatter
        'django.server': {
            '()': 'django.utils.log.ServerFormatter',
            'format': '[%(server_time)s] %(message)s',
        }
    },
    'handlers': {
        # django's default handler...
        'django.server': {
            'level': 'INFO',
            'filters': ['skip_static_requests'],  # <- ...with one change
            'class': 'logging.StreamHandler',
            'formatter': 'django.server',
        },
    },
    'loggers': {
        # django's default logger
        'django.server': {
            'handlers': ['django.server'],
            'level': 'INFO',
            'propagate': False,
        },
    }
}

以下是自1.10开始的所有Django默认记录器,您可以使用相同的方式覆盖它们: https://github.com/django/django/blob/32265361279b3316f5bce8efa71f2049409461e3/django/utils/log.py#L18

以下是Django默认内置记录器的功能描述: https://docs.djangoproject.com/en/1.10/topics/logging/#id3

以上是Django上CallbackFilter用于挂钩自定义过滤器的文档: https://docs.djangoproject.com/en/1.10/topics/logging/#django.utils.log.CallbackFilter

答案 1 :(得分:3)

作为解决方法,您可以使用this snippet (from Django Snippets)

from django.conf import settings
from django.core.servers import basehttp
from django.core.management.commands.runserver import Command as BaseCommand

class QuietWSGIRequestHandler(basehttp.WSGIRequestHandler):
    def log_message(self, format, *args):
        # Don't bother logging requests for paths under MEDIA_URL.
        if self.path.startswith(settings.MEDIA_URL):
            return
        # can't use super as base is old-style class, so call method explicitly
        return basehttp.WSGIRequestHandler.log_message(self, format, *args)

def run(addr, port, wsgi_handler):
    server_address = (addr, port)
    httpd = basehttp.WSGIServer(server_address, QuietWSGIRequestHandler)
    httpd.set_app(wsgi_handler)
    httpd.serve_forever()

class Command(BaseCommand):
    def handle(self, addrport='', *args, **options):
        # monkeypatch Django to use our quiet server
        basehttp.run = run
        return super(Command, self).handle(addrport, *args, **options)

您需要使用此命令来运行服务器。它基本上只覆盖日志行为以删除以MEDIA_URL设置开头的请求。将整个文件放在已安装的应用程序中并使用./manage.py runserver_quiet运行(如果命令文件为runserver_quiet.py

您无法使用logging模块,因为WSGIRequestHandler并未使用它来显示这些消息。 It is directly written in the stderr stream

答案 2 :(得分:1)

从Django 1.10开始,您可以将django.server日志记录配置为“处理由runserver命令调用的服务器接收的请求”。这是过滤媒体请求并专注于记录器信息的快速方法。

添加到django日志记录设置:

loggers: {
....
    'django.server': {
        'handlers': ['console'],
        'level': 'ERROR'  # or INFO if you want to see the log
    },
}

Django文档参考:Logging: django-server

答案 3 :(得分:0)

from django.core.servers.basehttp import WSGIRequestHandler

# Grab the original log_message method.
_log_message = WSGIRequestHandler.log_message

def log_message(self, *args):
    # Don't log if path starts with /static/
    if self.path.startswith("/static/"):
        return
    else:
        return _log_message(self, *args)

# Replace log_message with our custom one.
WSGIRequestHandler.log_message = log_message

# Import the original runserver management command
from django.core.management.commands.runserver import Command

帽子提示https://code.djangoproject.com/ticket/25704