我编写了一个Erlang OTP服务器来处理游戏中的单个子弹。当我开始这个过程时,我希望它开始一个递归函数,每个请求都有一些延迟。我的问题是这种延迟似乎没有发生。我不认为'转发'的处理信息根本要求......我做错了什么?
服务器启动后,所有REPEATER字符串都会打印在终端中,没有延迟......
这是从另一台服务器发出的启动子弹的调用:
{ok,BullPid} = gen_server:start('bullet', [self(), Type, Direction, Pos, ClientMaster], []),
这是服务器:
-module('bullet').
-export([init/1, handle_info/2, handle_cast/2, terminate/2]).
repeater(0) ->
exit(normal);
repeater(Counter) ->
io:fwrite("REPEATER\n"),
erlang:send_after(100, self(), forward),
repeater(Counter-1).
init([Client, _Type, Direction, StartPos, ClientMaster]) ->
gen_server:cast(self(), startRepeater),
io:fwrite("BULLET INITED!!"),
Size = {10, 10},
{ok, {Direction, {StartPos, Size, Client}, ClientMaster}}.
handle_cast(startRepeater, {Direction, Bullet, ClientMaster}) ->
repeater(200),
{noreply, {Direction, Bullet, ClientMaster}}.
handle_info(forward, {Direction, {Pos, Size, Client}, ClientMaster}) ->
io:fwrite("forward"),
Hit = gen_server:call(ClientMaster, {bullet, {Pos, Size, Client}, Direction}),
case Hit of
{NewPos, object} ->
io:fwrite("OBJECT"),
gen_server:cast(Client, {updateBullet, {Direction, NewPos, self()}}),
exit(normal);
{NewPos, ID} ->
io:fwrite("ID"),
gen_server:cast(Client, {updateBullet, {Direction, NewPos, self()}}),
ID ! {hit, Client},
Client ! {frag, ID},
exit(normal);
{NewPos, move} ->
io:fwrite("MOVE"),
gen_server:cast(Client, {updateBullet, {Direction, NewPos, self()}})
end,
{noreply, {Direction, NewPos, ClientMaster}}.
terminate(_Reason, {_Direction, {_StartPos, _Size, Client}, _ClientMaster}) ->
gen_server:cast(Client, {removeBullet, self()}),
io:fwrite("bullet ~p terminated!\n", [self()]),
ok.
答案 0 :(得分:2)
您启动"转发器的方式"是错的。它的编写方式,每个转发器消息将在100毫秒后加到您的进程邮箱(加上调用转发器本身的任何延迟)。
您只需将Counter
乘以您正在使用的超时即可解决此问题。例如:
repeater(0) ->
ok; % don't exit here; exit after you *receive* the last forward message
repeater(Counter) ->
io:fwrite("REPEATER\n"),
erlang:send_after(100 * Counter, self(), forward),
repeater(Counter-1).
使用此功能,您将收到Counter
转发消息,每个消息由大致 100毫秒分隔。