Question

我在表格问题和表格答案中有一个查看列。表格问题有id和问题文本，而表格答案有id，question_id（来自表格问题的fk）和答案文本。

SELECT     
    QuestionID, QuestionTxt, [1], [2], [3], [4]
FROM         
    (SELECT     
         ROW_NUMBER() OVER (PARTITION BY QuestionID
                            ORDER BY newid()) AnswerInQuestionID, 
         a.AnswerTxt, q.QuestionTxt, q.QuestionId
     FROM         
         dbo.TblQuestion q 
     JOIN
         dbo.TblAnswer a ON q.QuestionId = a.answer_question_id) A 
PIVOT (MAX(a.AnswerTxt) FOR AnswerInQuestionID IN ([1], [2], [3], [4])) AS piv

从这个SQL中，我可以随机化答案，但它只显示文本。我想要文本答案和它的id

Answer 1

很难从你的问题中找出你希望获得AnswerID的地方。如果您想将它放在一个列中，则需要使用@ StayPuft的答案。如果您希望它作为文本列的一部分，您可以使用下面的SQL：

SELECT questionText, [1], [2], [3]
FROM
(
    SELECT 
        ROW_NUMBER() OVER (PARTITION BY QuestionID ORDER BY newid()) AnswerInQuestionID,
        CAST(AnswerID AS VARCHAR(20)) + ' - ' + answerTxt AS answerTxt, 
        QuestionText
    FROM questions q
        JOIN answers a
            ON q.QuestionID=a.answer_question_id
) A
PIVOT
(
    MAX(answerTxt)
    FOR AnswerInQuestionID IN ([1], [2], [3] )
) as piv

如果您希望将它们作为三个单独的列，则可以使用以下SQL：

SELECT 
  questionText, 
  LEFT([1], 1) AS AnswerID1,
  RIGHT([1], LEN([1]) - 1) AS AnswerText1,
  LEFT([2], 1) AS AnswerID2,
  RIGHT([1], LEN([1]) - 1) AS AnswerText1,
  LEFT([3], 1) AS AnswerID3,
  RIGHT([2], LEN([3]) - 1) AS AnswerText3
FROM
(
  SELECT 
  ROW_NUMBER() OVER (PARTITION BY QuestionID ORDER BY newid()) AnswerInQuestionID,
  CAST(AnswerID AS VARCHAR(20)) + answerTxt AS answerTxt, 
  QuestionText
  FROM questions q
  JOIN answers a
  ON q.QuestionID=a.answer_question_id
) A
PIVOT
(
  MAX(answerTxt)
  FOR AnswerInQuestionID IN ([1], [2], [3] )
) as piv

编辑：添加了CHARINDEX（）函数和管道（'|'）以允许不同的数字长度。可能有更简洁的方法，但这对我有用：

SELECT 
  questionText, 
  LEFT([1], CHARINDEX('|', [1]) -1) AS AnswerID1,
  RIGHT([1], LEN([1]) - CHARINDEX('|', [1])) AS AnswerText1,
  LEFT([2], CHARINDEX('|', [2]) -1) AS AnswerID2,
  RIGHT([2], LEN([2]) -  CHARINDEX('|', [2])) AS AnswerText2,
  LEFT([3], CHARINDEX('|', [3]) -1) AS AnswerID3,
  RIGHT([3], LEN([3]) -  CHARINDEX('|', [3])) AS AnswerText3
FROM
(
  SELECT 
  ROW_NUMBER() OVER (PARTITION BY QuestionID ORDER BY newid()) AnswerInQuestionID,
  CAST(AnswerID AS VARCHAR(20)) +'|'+ answerTxt AS answerTxt, 
  QuestionText
  FROM questions q
  JOIN answers a
  ON q.QuestionID=a.answer_question_id
) A
PIVOT
(
  MAX(answerTxt)
  FOR AnswerInQuestionID IN ([1], [2], [3] )
) as piv

Answer 2

看起来a.AnswerTxt不在你的主要选择中，只有QuestionID和QuestionTxt。将a.AnswerTxt添加到第一行。

Answer 3

首先让我说SQL Fiddle真棒！

如果你想显示答案ID - 这就是我所做的：

SELECT questionText, [1], [2], [3], answerID
FROM
(
    SELECT 
        ROW_NUMBER() OVER (PARTITION BY QuestionID ORDER BY newid()) AnswerInQuestionID,
    answerTxt,
    QuestionText,
    answerID
FROM questions q
    JOIN answers a
        ON q.QuestionID=a.answer_question_id
   ) A
    PIVOT
    (
        MAX(answerTxt)
        FOR AnswerInQuestionID IN ([1], [2], [3] )
    ) as piv

从表中选择带有文本的id进入视图

3 个答案: