Question

我在处理Paramiko中的超时错误时遇到问题。下面与我用来连接的内容类似。

try:
    dssh = paramiko.SSHClient()
    dssh.set_missing_host_key_policy(paramiko.AutoAddPolicy())
    dssh.connect(IP, username, password)  
    stdin, stdout, stderr = dssh.exec_command('sho run')
    status = 'success'
except paramiko.AuthenticationException:
    status = 'fail'

当主机出现故障时，我会收到如下所示的错误，并且脚本将中止。

Traceback (most recent call last):
  File "ssh3.py", line 23, in <module>
    dssh.connect(IP, username, password)
  File "/usr/lib/python2.7/site-packages/paramiko/client.py", line 296, in connect
    sock.connect(addr)
  File "/usr/lib/python2.7/socket.py", line 224, in meth
    return getattr(self._sock,name)(*args)
socket.error: [Errno 116] Connection timed out

有没有办法捕获此错误并允许脚本从头开始运行？

Answer 1

当然。您只需要捕获正在引发的异常。

# At the beginning of your code:
import socket

# In your loop
try:
    # Your stuff
# Replace the existing exception handler:
except (socket.error, paramiko.AuthenticationException):
    status = 'fail'

Python - SSH到IP地址列表。连接超时的异常处理

1 个答案: