解压缩到元组之间Python有什么区别:
x, y, z = v
并解压缩到列表中?
[x, y, z] = v
答案 0 :(得分:10)
绝对没有,甚至到字节码(使用dis
):
>>> def list_assign(args):
[x, y, z] = args
return x, y, z
>>> def tuple_assign(args):
x, y, z = args
return x, y, z
>>> import dis
>>> dis.dis(list_assign)
2 0 LOAD_FAST 0 (args)
3 UNPACK_SEQUENCE 3
6 STORE_FAST 1 (x)
9 STORE_FAST 2 (y)
12 STORE_FAST 3 (z)
3 15 LOAD_FAST 1 (x)
18 LOAD_FAST 2 (y)
21 LOAD_FAST 3 (z)
24 BUILD_TUPLE 3
27 RETURN_VALUE
>>> dis.dis(tuple_assign)
2 0 LOAD_FAST 0 (args)
3 UNPACK_SEQUENCE 3
6 STORE_FAST 1 (x)
9 STORE_FAST 2 (y)
12 STORE_FAST 3 (z)
3 15 LOAD_FAST 1 (x)
18 LOAD_FAST 2 (y)
21 LOAD_FAST 3 (z)
24 BUILD_TUPLE 3
27 RETURN_VALUE
答案 1 :(得分:2)
没有。实际上x, y, z = v
是以下的简写:
(x, y, z) = v
...正在元组中解压缩。发生了同样的行为:
>>> v = (1, 3, 4)
>>> [x, y, z] = v
>>> x, y, z
(1, 3, 4)
>>> x, y, z = v
>>> x, y, z
(1, 3, 4)