Question

我在Android上有应用程序将一个zip文件发送到PHP服务器。 zip文件里面有多张图片。什么是接收此文件流并生成zip文件并将其解压缩的正确方法。

目前我正在接收带有此PHP代码的zip文件，但它是.txt格式，我可以在里面找到所有图片名称，但当然图片格式不可读。

$data = file_get_contents("php://input");

if($data === null){
    die ("No data Received");
}



$handler = fopen('new.txt', 'w+');
fclose($handler);
file_put_contents('new.txt',$data );

这是Android端的代码。

FileInputStream fileInputStream = new FileInputStream(new File(pathToOurFile) );

            URL url = new URL(urlServer);
            connection = (HttpURLConnection) url.openConnection();

            // Allow Inputs &amp; Outputs.
            connection.setDoInput(true);
            connection.setDoOutput(true);
            connection.setUseCaches(false);

            // Set HTTP method to POST.
            connection.setRequestMethod("POST");

            connection.setRequestProperty("Connection", "Keep-Alive");
            connection.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary);

            outputStream = new DataOutputStream( connection.getOutputStream() );
            outputStream.writeBytes(twoHyphens + boundary + lineEnd);
            outputStream.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + pathToOurFile +"\"" + lineEnd);
            outputStream.writeBytes(lineEnd);

            bytesAvailable = fileInputStream.available();
            bufferSize = Math.min(bytesAvailable, maxBufferSize);
            buffer = new byte[bufferSize];

            // Read file
            bytesRead = fileInputStream.read(buffer, 0, bufferSize);

            while (bytesRead > 0)
            {
                outputStream.write(buffer, 0, bufferSize);
                bytesAvailable = fileInputStream.available();
                bufferSize = Math.min(bytesAvailable, maxBufferSize);
                bytesRead = fileInputStream.read(buffer, 0, bufferSize);
            }

            outputStream.writeBytes(lineEnd);
            outputStream.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);

            // Responses from the server (code and message)
            int serverResponseCode = connection.getResponseCode();
            String serverResponseMessage = connection.getResponseMessage();

            fileInputStream.close();
            outputStream.flush();
            outputStream.close();
        }
        catch (Exception ex)
        {
            //Exception handling
        }

如何从Android发送的PHP服务器上接收zip文件

0 个答案: