Question

我有两个下拉菜单。我希望无论何时在任何一个下拉列表中进行选择，都会调用一个名为intersect的函数，该函数又调用函数loadData和loadData1.My代码附加在这里。

<select onchange="intersect()" id="metric" class="wrapper-dropdown">
<option value ="190">190</option>
    <option value ="90">90</option>
    <option value ="100">100</option>
    <option value ="300">300</option>
</select>

<select onchange="intersect()" id="metric1" class="wrapper-dropdown">
<option value ="100">100</option>
    <option value ="200">200</option>
    <option value ="0">0</option>
</select>
<script>

var intersect= function() {

var total_90 = function() {
var data = [
 {date: "2011-11-14T16:17:54Z", quantity: 2, total: 190, tip: 100, type: "tab"},
 {date: "2011-11-14T16:20:19Z", quantity: 2, total: 190, tip: 100, type: "tab"},
 {date: "2011-11-14T16:28:54Z", quantity: 1, total: 300, tip: 200, type: "visa"},
 {date: "2011-11-14T16:30:43Z", quantity: 2, total: 90, tip: 0, type: "tab"},
 {date: "2011-11-14T16:48:46Z", quantity: 2, total: 90, tip: 0, type: "tab"},
 {date: "2011-11-14T16:53:41Z", quantity: 2, total: 90, tip: 0, type: "tab"},
 {date: "2011-11-14T16:54:06Z", quantity: 1, total: 100, tip: 0, type: "cash"},
 {date: "2011-11-14T16:58:03Z", quantity: 2, total: 90, tip: 0, type: "tab"},
 {date: "2011-11-14T17:07:21Z", quantity: 2, total: 90, tip: 0, type: "tab"},
 {date: "2011-11-14T17:22:59Z", quantity: 2, total: 90, tip: 0, type: "tab"},
 {date: "2011-11-14T17:25:45Z", quantity: 2, total: 200, tip: 0, type: "cash"},
 {date: "2011-11-14T17:29:52Z", quantity: 1, total: 200, tip: 100, type: "visa"}
 ];
 var ndx = crossfilter(data);
 var totalDim = ndx.dimension(function(d) { return d.total; });  
 var total_90 =     totalDim.filter(document.getElementById('metric').selectedOptions[0].value); 
return total_90;
  };
var tip_90 = function() {
var data = [
{date: "2011-11-14T16:17:54Z", quantity: 2, total: 190, tip: 100, type: "tab"},
{date: "2011-11-14T16:20:19Z", quantity: 2, total: 190, tip: 100, type: "tab"},
{date: "2011-11-14T16:28:54Z", quantity: 1, total: 300, tip: 200, type: "visa"},
{date: "2011-11-14T16:30:43Z", quantity: 2, total: 90, tip: 0, type: "tab"},
{date: "2011-11-14T16:48:46Z", quantity: 2, total: 90, tip: 0, type: "tab"},
{date: "2011-11-14T16:53:41Z", quantity: 2, total: 90, tip: 0, type: "tab"},
{date: "2011-11-14T16:54:06Z", quantity: 1, total: 100, tip: 0, type: "cash"},
{date: "2011-11-14T16:58:03Z", quantity: 2, total: 90, tip: 0, type: "tab"},
{date: "2011-11-14T17:07:21Z", quantity: 2, total: 90, tip: 0, type: "tab"},
{date: "2011-11-14T17:22:59Z", quantity: 2, total: 90, tip: 0, type: "tab"},
{date: "2011-11-14T17:25:45Z", quantity: 2, total: 200, tip: 0, type: "cash"},
{date: "2011-11-14T17:29:52Z", quantity: 1, total: 200, tip: 100, type: "visa"}
];
 var ndx = crossfilter(data);
 var tipDim = ndx.dimension(function(d) { return d.tip; });  
 var tip_90 = tipDim.filter(document.getElementById('metric1').selectedOptions[0].value); 
 return tip_90;
 }
 var result = [];

   for (var i = 0; i < total_90.length; i++){
        if (total_90[i].total == 90 && total_90[i].tip == 0)
        {

            result.push(total_90[i]);
        }
    }

   for (var i = 0; i < tip_90.length; i++){
        if (tip_90[i].total == 90 && tip_90[i].tip == 0)
        {
            result.push(tip_90[i]);
        }
    }
function print_filter(filter){
var f=eval(filter);
if (typeof(f.length) != "undefined") {}else{}
if (typeof(f.top) != "undefined") {f=f.top(Infinity);}else{}
if (typeof(f.dimension) != "undefined") {f=f.dimension(function(d) { return "";}).top(Infinity);}else{}
console.log(filter+"("+f.length+") = "+JSON.stringify(f).replace("[","   [\n\t").replace(/}\,/g,"},\n\t").replace("]","\n]"));
    } 
    print_filter("result"); 
     }
    </script>
    </body>

所以，在任何给定的情况下，如果我选择＆＃39; 90＆＃39;在第一次下拉和＆＃39; 0＆＃39;已在第二个下拉列表中选中，然后我希望在控制台上打印来自两个总数= 90且tip = 0的JSON数组中的所有行。

Answer 1

我不知道这里有什么困难......

我希望无论何时在任何一个下拉列表中进行选择，都会调用一个名为intersect的函数，该函数又会调用函数loadData和loadData1。

<select onchange="intersect()" id="metric" class="wrapper-dropdown">
    <option value ="190">190</option>
    <option value ="90">90</option>
    <option value ="100">100</option>
    <option value ="300">300</option>
</select>

<select onchange="intersect()" id="metric1" class="wrapper-dropdown">
    <option value ="100">100</option>
    <option value ="200">200</option>
    <option value ="0">0</option>
</select>

与

function loadData() {
    alert("loadData reached");
}
function loadData1() {
    alert("loadData1 reached");
}
function intersect() {
    loadData();    
    loadData1();
}

示例：Fiddle

Answer 2

我不确定您为什么要使用d3.js和crossfilter.js我认为您的问题没有必要。

由于您只在问题中标记javascript。我特此为您提供纯JS解决方案，而不是jquery

var m1 = document.getElementById('metric');

var m2 = document.getElementById('metric1');

m1.onchange = function(){
    //alert(m1.value);
    //alert(m2.value);
    var result = intersection(data, data1, m1.value, m2.value);

    if (result != ""){
        for (var i = 0; i < result.length; i++){
            console.log(result[i]);
        }
    }   
}

m2.onchange = function(){

    var result = intersection(data, data1, m1.value, m2.value);

    if (result != ""){
        for (var i = 0; i < result.length; i++){
            console.log(result[i]);
        }
    }
}

//a is the data
//b is the data1
//v1 is the metric value
//v2 is the matric1 value
function intersection(a, b, v1, v2)
{
    var result = [];
    var c = a.concat(b);
    for (var i = 0; i < c.length; i++){

        if (c[i].total == v1 && c[i].tip == v2)
        {                             
            result.push(c[i]);
        }
    }
    return result;
}

JSFiddle尝试使用total = 90和tip = 0进行选择。您将得到所谓的＃34;十字路口＆＃34;你想要的结果。

使用下拉列表进行交叉过滤

2 个答案: