Question

我有一张桌子，可以通过手动打孔机存储员工的出勤情况。它作为最后一个逻辑中的第一个工作，并显示了员工的出勤率。

现在我想在整个月内准备整个部门的员工出勤表单

管理层提出的表格形式是

Employee Name  | 1 | 2 | 3 | 4 | 5 |6 |..... so on to the days in a month 
John Carpenter | P | P | A | A | P | LFP
John Seraph A  | P | P | A | A | P | LFP

我们在后端有SQL Server 2000，前端是在C＃上开发的。我们将使用水晶报告。

表格结构：

tbl_Attendance tbl_department tbl_employee tbl_employeeShifts tbl_leaves tbl_shifts

CREATE TABLE [dbo].[tbl_Attendance] (
    [AttendanceID] [bigint] IDENTITY (1, 1) NOT NULL ,
    [PNO] [bigint] NULL ,
    [AttDate] [datetime] NULL ,
    [CurrentShift] [varchar] (50) COLLATE SQL_Latin1_General_CP1_CI_AS NULL ,
    [ReaderID] [bigint] NULL ,
    [Status] [varchar] (50) COLLATE SQL_Latin1_General_CP1_CI_AS NULL ,
    [flag] [char] (10) COLLATE SQL_Latin1_General_CP1_CI_AS NULL ,
    [ManualFlag] [char] (10) COLLATE SQL_Latin1_General_CP1_CI_AS NULL 
) ON [PRIMARY]
GO

CREATE TABLE [dbo].[tbl_Department] (
    [DeptID] [bigint] IDENTITY (1, 1) NOT NULL ,
    [DeptName] [varchar] (50) COLLATE SQL_Latin1_General_CP1_CI_AS NULL 
) ON [PRIMARY]
GO

CREATE TABLE [dbo].[tbl_Employee] (
    [EmpID] [bigint] IDENTITY (1, 1) NOT NULL ,
    [PNO] [varchar] (50) COLLATE SQL_Latin1_General_CP1_CI_AS NULL ,
    [T1] [char] (10) COLLATE SQL_Latin1_General_CP1_CI_AS NULL ,
    [T2] [char] (10) COLLATE SQL_Latin1_General_CP1_CI_AS NULL ,
    [T3] [char] (10) COLLATE SQL_Latin1_General_CP1_CI_AS NULL ,
    [T4] [char] (10) COLLATE SQL_Latin1_General_CP1_CI_AS NULL ,
    [T5] [char] (10) COLLATE SQL_Latin1_General_CP1_CI_AS NULL ,
    [T6] [char] (10) COLLATE SQL_Latin1_General_CP1_CI_AS NULL ,
    [T7] [char] (10) COLLATE SQL_Latin1_General_CP1_CI_AS NULL ,
    [T8] [char] (10) COLLATE SQL_Latin1_General_CP1_CI_AS NULL ,
    [T9] [char] (10) COLLATE SQL_Latin1_General_CP1_CI_AS NULL ,
    [CreatedDate] [datetime] NULL ,
    [EmpName] [varchar] (100) COLLATE SQL_Latin1_General_CP1_CI_AS NULL ,
    [Type] [varchar] (50) COLLATE SQL_Latin1_General_CP1_CI_AS NULL 
) ON [PRIMARY]
GO

CREATE TABLE [dbo].[tbl_EmployeeShifts] (
    [EmpShiftID] [bigint] IDENTITY (1, 1) NOT NULL ,
    [EmpID] [bigint] NULL ,
    [ShiftID] [bigint] NULL ,
    [DateFrom] [datetime] NULL ,
    [DateTo] [datetime] NULL ,
    [CreatedDate] [datetime] NULL ,
    [DeptID] [bigint] NULL ,
    [flag] [bit] NULL ,
    [uFlag] [char] (10) COLLATE SQL_Latin1_General_CP1_CI_AS NULL 
) ON [PRIMARY]
GO

CREATE TABLE [dbo].[tbl_LoginTime] (
    [LoginTimeID] [bigint] IDENTITY (1, 1) NOT NULL ,
    [UserID] [bigint] NULL ,
    [LoginTime] [datetime] NULL 
) ON [PRIMARY]
GO

CREATE TABLE [dbo].[tbl_Permission] (
    [EmpPermissionID] [bigint] IDENTITY (1, 1) NOT NULL ,
    [EmpID] [bigint] NULL ,
    [DateFrom] [datetime] NULL ,
    [DateTo] [datetime] NULL ,
    [Type] [varchar] (50) COLLATE SQL_Latin1_General_CP1_CI_AS NULL ,
    [CreatedDate] [datetime] NULL ,
    [flag] [char] (10) COLLATE SQL_Latin1_General_CP1_CI_AS NULL 
) ON [PRIMARY]
GO

CREATE TABLE [dbo].[tbl_Shifts] (
    [ShiftID] [bigint] IDENTITY (1, 1) NOT NULL ,
    [StartShift] [varchar] (20) COLLATE SQL_Latin1_General_CP1_CI_AS NULL ,
    [EndShift] [varchar] (20) COLLATE SQL_Latin1_General_CP1_CI_AS NULL ,
    [CreatedDate] [datetime] NULL ,
    [GraceTime] [varchar] (50) COLLATE SQL_Latin1_General_CP1_CI_AS NULL ,
    [ShiftType] [varchar] (20) COLLATE SQL_Latin1_General_CP1_CI_AS NULL 
) ON [PRIMARY]
GO

CREATE TABLE [dbo].[tbl_UserInfo] (
    [UserID] [bigint] IDENTITY (1, 1) NOT NULL ,
    [UserName] [varchar] (50) COLLATE SQL_Latin1_General_CP1_CI_AS NULL ,
    [UserPassword] [varchar] (50) COLLATE SQL_Latin1_General_CP1_CI_AS NULL ,
    [CreatedDate] [datetime] NULL 
) ON [PRIMARY]

以上是表格结构。所有我想做一些加入并以这种格式获得报告。

如上所述

对查询逻辑的一点帮助将不胜感激。

Answer 1

您可以使用用于表格格式的交叉表报告。

Attandance report creation with cross-tab

cross-tab example

Cross-tab exmple2

如何以表格形式呈现员工出勤率

1 个答案: