Question

您好，谢谢您的时间。我最近一直试图通过学习Python 2.7 Zed A. Shaw“学习python的艰难方法”

在其中一个练习中，我遇到了一个小问题，但在那个问题上很麻烦。

代码如下：

from sys import argv
script, input_file = argv

def print_all(f):
    print f.read()

def rewind(f):
    f.seek(0)

def print_a_line(line_count, f):
    print line_count, f.readline()

current_file = open(input_file)
print "First let's print the whole file:\n"
print_all(current_file)
print "now let's rewind it kind off like a tape."
rewind(current_file)
print "let's print three lines."
current_line = 1 
print_a_line(current_line, current_file)
current_line += 1
print_a_line(current_file, current_file)
current_line += 1
print_a_line(current_line, current_file)

结果是：

First let's print the whole file:

To all the people out there.
I say I don't like my hair.
I need to shave it off.

Now let's rewind it kind off like a tape.
let's print three lines.
1 To all the people out there.

<open file 'test.txt', mode 'r' at 0x01D16230> I say I don't like my hair.

3 I need to shave it off.

除了<open file 'test.txt', mode 'r' at 0x01D16230>之外，一切都工作得很好，这对我的单纯思维似乎是随机的。

为什么会出现这种情况？

注意：我在Windows 8.1上使用notepad ++

Answer 1

print_a_line(current_file, current_file)

这应该是

print_a_line(current_line, current_file)

你看到的输出是因为

print line_count

其中line_count实际上是指之前为阅读而打开的文件流。

Python代码乱码

1 个答案: