Question

早上好。我需要帮助。

我有这段代码：

select A.AREA_CODE, A.OUTLET_NAME, SUM(B.AMOUNT) as NETSALES
from M_OUTLET A, T_SALES_DETAIL B 
where A.OUTLET_NO = B.OUTLET_NO and A.OUTLET_TYPE_DESC not
like '%head%' and A.OUTLET_TYPE_DESC not like '%prod%' and 
A.OUTLET_TYPE_DESC not like '%stor%'
and B.SYSTEM_DATE  between CONVERT (datetime, '3/1/2014') 
and CONVERT (datetime, '3/31/2014')
and B.VOID = 'N' group by A.AREA_CODE , A.OUTLET_NAME order by A.AREA_CODE

这是输出：

AREA_CODE    OUTLET_NAME          NETSALES
1         MAKATI BU CAFE 2        226202.52
2         MAKATI BU CART          170305.01

其他代码是：

SELECT A.AREA_CODE, SUM (C.AMOUNT) AS E_SALES 
FROM E_SALES_DETAIL C , M_OUTLET A 
WHERE C.SYSTEM_DATE
between CONVERT (datetime, '3/1/2014') and 
CONVERT (datetime, '3/31/2014') and C.VOID = 'N'
GROUP BY A.AREA_CODE ORDER BY A.AREA_CODE

，输出为：

AREA_CODE     E_SALES
1            22208347.35
2            14453051.45

我的问题是，如何加入此代码才能获得此输出：

AREA_CODE    OUTLET_NAME             E_SALES               NETSALES
    1         MAKATI BU CAFE 2      22208347.35             226202.52
    2         MAKATI BU CART        14453051.45             170305.01

谢谢。

Answer 1

最简单的方法是将两个查询用作子查询。也就是说，我认为你在第二个子查询中缺少join条件：

select ab.area_code. ab.outlet_name, ab.netsales, ac.e_sales
from (select A.AREA_CODE, A.OUTLET_NAME, SUM(B.AMOUNT) as NETSALES
      from M_OUTLET A join
           T_SALES_DETAIL B 
           on A.OUTLET_NO = B.OUTLET_NO 
      where A.OUTLET_TYPE_DESC not like '%head%' and
            A.OUTLET_TYPE_DESC not like '%prod%' and 
            A.OUTLET_TYPE_DESC not like '%stor%' and
            B.SYSTEM_DATE between CONVERT(datetime, '3/1/2014') and CONVERT(datetime, '3/31/2014') and
            B.VOID = 'N'
      group by A.AREA_CODE, A.OUTLET_NAME
     ) ab join
     (SELECT A.AREA_CODE, SUM(C.AMOUNT) AS E_SALES 
      FROM E_SALES_DETAIL C join
           M_OUTLET A 
           ON ????
      WHERE C.SYSTEM_DATE between CONVERT(datetime, '3/1/2014') and CONVERT(datetime, '3/31/2014')  and
            C.VOID = 'N'
      GROUP BY A.AREA_CODE 
     ) ac
     on ab.area_code ac.area_code;

如何加入两个查询的输出

1 个答案: