Question

我在Mongo中运行查询，以便我只能显示除帐户ID以外的所有子模式。但是，作为回调＆＃34; list_data＆＃34;的结果，我得到了未定义。这就是我的查询在我的路线中写的方式：

exports.list_data = function(req, res){
  models.Director.find({})
  .populate("full_name").populate("dob").populate("favorite_movies").populate("favorite_camera")
  .exec(function(err, list_data){
    res.render('users', {"dirs": list_data});
  })
};

这是我的模特：

var mongoose = require('mongoose');
mongoose.connect('mongodb://localhost/lvsAPI');
var db = mongoose.connection;
db.on('error', console.error.bind(console, 'connection error:'));

//set schema
var Schema = mongoose.Schema;

var directorSchema = new Schema ({
  account_id: Number,
  full_name: String,
  dob: Date,
  favorite_camera: String,
  favorite_movies: String
});

var Director = mongoose.model("Director", directorSchema);

module.exports = {"Director": Director};

Answer 1

这很简单没有结果。并且您的架构使用populate（）时出错了。请参阅official docs并正确执行：

var mongoose = require('mongoose')
, Schema = mongoose.Schema     

var personSchema = Schema({
  _id     : Number,
  name    : String,
  age     : Number,
  stories : [{ type: Schema.Types.ObjectId, ref: 'Story' }]
});

var storySchema = Schema({
  _creator : { type: Number, ref: 'Person' },
  title    : String,
  fans     : [{ type: Number, ref: 'Person' }]
});

var Story  = mongoose.model('Story', storySchema);
var Person = mongoose.model('Person', personSchema);

ref 选项告诉Mongoose在填充期间使用哪个模型。现在＆＃39; ref＆＃39;字段将填充：

Story
 .findOne({ title: 'Once upon a timex.' })
 .populate('_creator')
 .exec(function (err, story) {
    if (err) return handleError(err);
    console.log('The creator is %s', story._creator.name);
    // prints "The creator is Aaron"
 })

Population docs

Mongoose Populate回调未定义

1 个答案: