Question

int main (int argc, const char * argv[])
 {
     @selector(grades);

 }

-(int)grades:(int)grade{
    printf("Please write down your grade:");  
    scanf("%d", &grade);/*the grade value written has assigned to grade parameter*/   
    printf("\n");

    if((grade > 100) || (grade <0)){/*This is a warning range of grades */
    printf("Warning!!\nYour grade is out of range\nPlease write a NUMBER between 0-100\n");
}
else{/*The grade ranges are defined*/
    if((0<=grade) && (grade<=20))
        NSLog(@"Your letter grade is : F\nyou failed\n");/*NSLog has been used insted of printf*/
    if((21<=grade) &&(grade<=40))
        NSLog(@"Your letter grade is : D\nTry again\n");
    if((41<=grade) && (grade<=60))
        NSLog(@"your letter grade is : C\nNot bad\n");
    if((61<=grade)&&(grade<=80))
        NSLog(@"Your letter grade is : B\nWell Done\n");
    if((81<=grade)&&(grade<=100))
        NSLog(@"your letter grade is : A\nGreat !!\n");
}
return 0;
}

我在方法声明中遇到问题我想我已经检查了它我找不到任何错误如果你们中的任何人能帮助我，那就太好了。谢谢

Answer 1

该方法没有上下文。该方法被声明为对象的实例方法-，但是没有与之关联的类。因此，在什么情况下声明该方法是未知的。

对于您的案例使用，

            int grade (int grade)
            {
                printf("Please write down your grade:");
                scanf("%d", &grade);/*the grade value written has assigned to grade parameter*/
                printf("\n");

                if((grade > 100) || (grade <0)){/*This is a warning range of grades */
                    printf("Warning!!\nYour grade is out of range\nPlease write a NUMBER between 0-100\n");
                }
                else{/*The grade ranges are defined*/
                    if((0<=grade) && (grade<=20))
                        NSLog(@"Your letter grade is : F\nyou failed\n");/*NSLog has been used insted of printf*/
                    if((21<=grade) &&(grade<=40))
                        NSLog(@"Your letter grade is : D\nTry again\n");
                    if((41<=grade) && (grade<=60))
                        NSLog(@"your letter grade is : C\nNot bad\n");
                    if((61<=grade)&&(grade<=80))
                        NSLog(@"Your letter grade is : B\nWell Done\n");
                    if((81<=grade)&&(grade<=100))
                        NSLog(@"your letter grade is : A\nGreat !!\n");
                }
                return 0;
            }

            int main(int argc, const char * argv[])
            {

                grade(0);
            }

Answer 2

我的印象是“缺少方法声明的上下文”（MCFMD）的问题已完全理解从不。

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与此同时，一些人抱怨说他们认为MCFMD问题已经成熟并得到了充分解决......我在一段时间内在代码中与33 MCFMD作战，这更像是在黑暗中拍摄。我希望那些对MCFMD问题有更多了解的人分享他们宝贵的知识或任何理解...... 非常感谢你的关注！

目标c缺少方法声明的上下文

2 个答案: