Question

您好我有2个表具有相同的列名（Id，FName，LName，DOB，Type，Contact，Add）。

现在我希望将所有数据作为一个单独的行从两个表中按照Fname的顺序获得相同的FName，LName和DOB。

我尝试使用交叉和联盟但不适合我。

  Select * from #t1 where FirstName in (select FirstName from #t2 ) and LastName in  (select LastName from #t2 ) and DateOfBirth in (select DateOfBirth from #t2 ) 
 UNION
Select * from #t2 where FirstName in (select FirstName from #t1 ) and LastName in  (select LastName from #t1 ) and DateOfBirth in (select DateOfBirth from #t1 )      order by FirstName ,LastName

由于

Answer 1

我会这样做，但我确信这是一种更简洁的方式...

SELECT T1.*
FROM T1
INNER JOIN T2 
    ON T2.FirstName = T1.FirstName
    AND T2.LastName = T1.LastName
    AND T2.DateOfBirth = T1.DateOfBirth
UNION ALL
SELECT T2.*
FROM T2
INNER JOIN T1 
    ON T1.FirstName = T2.FirstName
    AND T1.LastName = T2.LastName
    AND T1.DateOfBirth = T2.DateOfBirth

Answer 2

这将起作用

Select a.*,b.* from #t1 a join #t2 b on (a.FName=b.FName and a.LName=b.LName and a.DOB=b.DOB)

Answer 3

试试这个

SELECT T1.Id,
       T1.FName, 
       T1.LName,
       T1.DOB,
       T1.Type,
       T1.Contact,
       T1.Add
FROM #t1 T1 INNER JOIN #t2 T2
   ON  T1.FName=T2.FName
   AND T1.LName=T2.LName
   AND T1.dob=T2.dob

Answer 4

另一种解决方法是在union之后进行汇总。然后检查值是否显示必需的次数：

select firstname, lastname, dob
from ((select firstname, lastname, dob, 't1' as which
       from #t1
      ) union all
      (select firstname, lastname, dob, 't2' as which
       from #t2
      )
     ) t
group by firstname, lastname, dob
having count(distinct which) = 2;

从两个不同的表中获取公共数据

4 个答案: