Question

我希望在我的一个ViewControllers中的UIWebView中检测链接点击，然后启动一个新的ViewController，它基本上是另一个带有检测到的链接的UIWebView。

继承我的代码：

-(BOOL)webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType
{

    NSURL *url = [request URL];

    if (self.interceptLinks){

        UIStoryboard *storyboard = [UIStoryboard storyboardWithName:@"Main" bundle:nil];
        BrowserViewController *browser = [storyboard instantiateViewControllerWithIdentifier:@"browserViewController"];
        NSLog(@"sending url== %@", url);
        [browser openBrowserWithUrl:url];
        [self performSegueWithIdentifier:@"browserDetail" sender:self];

        return NO;
    }
    else {

        self.interceptLinks = TRUE;
        return YES;

    }

}

然后在BrowserViewController.h中

 @property (strong, nonatomic) NSURL *incomingURL;
 @property (strong, nonatomic) IBOutlet UIWebView *browserView;
 - (void)openBrowserWithUrl:(NSURL *)url;

然后在BrowserViewController.m

中

- (void)openBrowserWithUrl:(NSURL *)url
{
    self.incomingURL = url;
    NSLog(@"incomming_URL==%@", self.incomingURL);
}


- (void)viewDidLoad
{
    [super viewDidLoad];
    NSLog(@"viewDidLoad_url == %@", self.incomingURL);


    self.browserView.delegate = self;
    self.browserView = [[UIWebView alloc] initWithFrame:CGRectMake(0, 0, self.view.bounds.size.width, self.view.bounds.size.height)];
    [self.browserView loadRequest:[NSMutableURLRequest requestWithURL:self.incomingURL]];





[self.view addSubview:_browserView];
// Do any additional setup after loading the view.

}

＆gt; openBrowserWithUrl＆＃34;中的NSLog返回所需的NSURL，但内部的那个＆＃34; viewDidLoad＆＃34;返回null，我在这里做错了什么？

Answer 1

调用performSegueWithIdentifier实际上会实例化BrowserViewController的新实例。我不熟悉故事板，知道如何做到这一点，但有一个UIViewController回调可以让你知道何时执行segue，以便你可以传递incomingURL。

如果您想手动执行，而不是使用故事板，则可以用

替换performSegue来电

[self.navigationController pushViewController:browser animated:YES];

在viewDidLoad之后丢失NSURL属性

1 个答案: