Question

这是我的课程，用于开启，关闭和覆盖树莓中的LED闪烁我想在一段时间内停止线程闪烁... 但线程不会在后台运行......

类LED：

_GPIOPORT=None
flagstop=0
flag=threading.Event()


def __init__(self,GPIONUM):
    self._GPIOPORT=GPIONUM
    GPIO.setmode(GPIO.BOARD)
    GPIO.setwarnings(False)
    GPIO.setup(self._GPIOPORT, GPIO.OUT)
    self.flag.set()


def TurnOn(self):
    self.flag.clear()
    print 'Turn On ...'
    GPIO.output(self._GPIOPORT,True)

def TurnOff(self):
    self.flag.clear()
    print 'Turn Off ...'
    GPIO.output(self._GPIOPORT,False)

def Blink(self,delay,e):
    print 'Thread Blink Create ...'
    t1=threading.Thread(self.BlinkThread(delay,e))
    t1.start()
    print 'Thread Started'

def BlinkThread(self,delaytime,event):
    print 'BlinkTrehad Start ....'
    while not event:
        GPIO.output(self._GPIOPORT,False)
        sleep(delaytime)
        GPIO.output(self._GPIOPORT,True)
        sleep(delaytime)

这是我使用此课程的模块：

import LED
from time import sleep
import threading

    if __name__ == '__main__':
        e=threading.Event()
        e.set()
        ledblue=LED.LED(11)
        ledblue.TurnOn()
        sleep(1)
        ledblue.Blink(1,e)
        ledblue.TurnOn()

从不在“线程启动”中打印consol并在行中循环运行

Answer 1

您在Thread构造函数中调用BlinkThread（）而不是仅传递函数引用和参数，并让线程启动该函数。将其更改为：

def Blink(self,delay,e):
    print 'Thread Blink Create ...'
    t1=threading.Thread(target=self.BlinkThread, args=(delay,e))
    t1.start()
    print 'Thread Started'

python线程不会在后台启动

1 个答案: