Question

我到处搜索这个但是找不到任何解决方案，我需要在下面的sql语句中首先列出一个像'New York'这样的特定城市，我试着放置按案例命令City.name_en 当'纽约'那么1 ELSE 2 END，City.name_en 在内部的sql语句中但是没有用，有没有解决方法呢？

SELECT * FROM (
SELECT RTRIM(Organization.name_en) as '@name','flag.png'  AS  '@flag',
    RTRIM(Country.name_en) as 'country',RTRIM(city.name_en) as 'city',Organization.id as 'OrganizationID',
    ROW_NUMBER() OVER (ORDER BY sequence_num) AS RowNum
FROM Organization 
LEFT JOIN City ON City.id = city_id
LEFT JOIN Country ON country.id = Organization.country_id
LEFT JOIN Industry ON Industry.id = Industry_id
WHERE 
 (industry_id =@industry_id OR Coalesce(@industry_id,'') = '')
AND (Organization.name_en LIKE '%' + @OrganizationName + '%' OR Coalesce(@OrganizationName,'') = '')
) AS SOD

WHERE    SOD.RowNum BETWEEN ((@PageNumber-1)*@RowsPerPage)+1
AND @RowsPerPage*(@PageNumber)

FOR XML PATH('organization'), ROOT('organizations')

Answer 1

使用ORDER BY FIELD
例如： -

ORDER BY FIELD(City.name_en, 'New York', 'CA')

它会给你预期的结果。

Answer 2

使用Union

示例

从country_name ='New York'

的国家/地区选择country_code，country_name

联合所有

从country_name！='New York'的国家/地区选择country_code，country_name 按country_name排序

Answer 3

其实我这样解决了：

ROW_NUMBER() OVER (ORDER BY CASE city.name_en
           WHEN @cityName THEN 1 
           ELSE 2 END ,city.name_en) AS RowNum

首先列出特定值

3 个答案: