Question

我正在加入2张桌子，我正在做

select distinct Package_id, package_title, durationindays,videourl,package_image_1,package_image_2,package_image_3,package_image_4,
package_image_5, Rating, AdultPrice
from packages
inner join
rates_and_dates on rates_and_dates.package = packages.package_id
where package_id=1 and adultprice='4500'

结果就像这样

ID | Package_title | DurationInDays | VideoUrl | Package_Image_1 | Package_Image_2          |Package_Image_3   | Package_Image_4  | Package_Image_5
001 | Title | 5 | www.youtube.com?1231 | www.images.com/image1 | www.images.com/image2     | wwww.images.com/image3 | www.images.com/image4 | image5

注意：所有图片都有不同的列

我想为所有5张图片只创建一列，所以结果应该是这样的

ID  |Package_title|DurationInDays | VideoUrl           | Package_Images        |
001 |Title        |5              | www.youtube.com?123| www.images.com/image1 |
    |             |               |                    | www.images.com/image2 |
    |             |               |                    | www.images.com/image3 |
    |             |               |                    | www.images.com/image4 |
    |             |               |                    | image5                |

请帮我解决这个问题。谢谢

Answer 1

select distinct Package_id, package_title, durationindays,videourl,package_image_1 + ',' + package_image_2 + ',' + package_image_3 + ',' + package_image_4 + ',' + package_image_5 As Pacakage,  Rating, AdultPrice
from packages
inner join
rates_and_dates on rates_and_dates.package = packages.package_id
where package_id=1 and adultprice='4500'

您可以使用任何分隔符而不是逗号。

Answer 2

您可以使用“UNION ALL”来完成此任务。

select distinct Package_id, package_title, durationindays,videourl,package_image_1 as package_image, Rating, AdultPrice
from packages
inner join
rates_and_dates on rates_and_dates.package = packages.package_id
where package_id=1 and adultprice='4500'
UNION ALL
select distinct Package_id, package_title, durationindays,videourl,package_image_2 as package_image, Rating, AdultPrice
from packages
inner join
rates_and_dates on rates_and_dates.package = packages.package_id
where package_id=1 and adultprice='4500'
UNION ALL
select distinct Package_id, package_title, durationindays,videourl,package_image_3 as package_image, Rating, AdultPrice
from packages
inner join
rates_and_dates on rates_and_dates.package = packages.package_id
where package_id=1 and adultprice='4500'
UNION ALL
select distinct Package_id, package_title, durationindays,videourl,package_image_4 as package_image, Rating, AdultPrice
from packages
inner join
rates_and_dates on rates_and_dates.package = packages.package_id
where package_id=1 and adultprice='4500'
UNION ALL
select distinct Package_id, package_title, durationindays,videourl,package_image_5 as package_image, Rating, AdultPrice
from packages
inner join
rates_and_dates on rates_and_dates.package = packages.package_id
where package_id=1 and adultprice='4500'

sql server使用join将列拆分为行

2 个答案: