Question

我最近尝试更改VBA代码

 Range("J2:J" & Cells(Rows.Count, "A").End(xlUp).Row).FormulaR1C1 = _
                "=INDEX(Accounts!R2C3:R491C3,MATCH(RC[-8],Accounts!R2C2:R491C2,0))"

到

 Range("J2:J" & Cells(Rows.Count, "A").End(xlUp).Row).FormulaR1C1 = _
                "=IFERROR(INDEX(Accounts!R2C3:R491C3,MATCH(RC[-8],Accounts!R2C2:R491C2,0)),"")"

但后面的代码收到错误。我有什么简单的遗失吗？

更新：使用以下代码发生同样的错误：

Range("J2:J" & Cells(Rows.Count, "A").End(xlUp).Row).FormulaR1C1 = _
        "=IFERROR((=INDEX(Accounts!R2C3:R" & lastrow & "C3,MATCH(RC[-8],Accounts!R2C2:R" & lastrow & "C2,0)),"""")"

在上文中，lastrow = Cells(Rows.Count, "A").End(xlUp).Row

Answer 1

您应该在公式中使用双引号：

Range("J2:J" & Cells(Rows.Count, "A").End(xlUp).Row).FormulaR1C1 = _
            "=IFERROR(INDEX(Accounts!R2C3:R491C3,MATCH(RC[-8],Accounts!R2C2:R491C2,0)),"""")"

在VBA中使用IFERROR功能

1 个答案: