Question

我是一名自学成才的新手，所以请耐心等待。我正在尝试创建一个允许用户上传其图像的网站。有了另一个用户的耐心，我能够得到一些答案，说明如何创建并允许用户将他们的图像上传到openshift上的数据驱动器上。但是，现在我需要能够将图像路径或URL存储到postgresql数据库（稍后可以调用），以便每个用户都能够跟踪他们上传的图像。我目前因此而受阻。以下是我认为在回答这个问题时起着重要作用的代码片段：

    class Todo(db.Model):
        __tablename__ = 'todos'
        id = db.Column('todo_id', db.Integer, primary_key=True)
        title = db.Column(db.String(60))
        text = db.Column(db.String)
        done = db.Column(db.Boolean)
        pub_date = db.Column(db.DateTime)
        user_id = db.Column(db.Integer, db.ForeignKey('users.user_id'))
        image_url = db.Column(db.String)

        def __init__(self, title, text, image_url):
            self.title = title
            self.text = text
            self.image_url = image_url
            self.done = False
            self.pub_date = datetime.utcnow()

    def allowed_file(filename):
        return '.' in filename and \
               filename.rsplit('.', 1)[1] in app.config['ALLOWED_EXTENSIONS']

    @app.route('/upload', methods=['POST'])
    def upload():
        # Get the name of the uploaded file
        file = request.files['file']
        # Check if the file is one of the allowed types/extensions
        if file and allowed_file(file.filename):
            # Make the filename safe, remove unsupported chars
            filename = secure_filename(file.filename)
            # Move the file form the temporal folder to
            # the upload folder we setup
            file.save(os.path.join(app.config['UPLOAD_FOLDER'], filename))
            # Redirect the user to the uploaded_file route, which
            # will basicaly show on the browser the uploaded file
            return redirect(url_for('uploaded_file',
                                    filename=filename))

    @app.route('/uploads/<filename>')
    def uploaded_file(filename):
        return send_from_directory(app.config['UPLOAD_FOLDER'],
                                   filename)

    @app.route('/new', methods=['GET', 'POST'])
    @login_required
    def new():
        if request.method == 'POST':
            if not request.form['title']:
                flash('Title is required', 'error')
            elif not request.form['text']:
                flash('Text is required', 'error')
            else:
                todo = Todo(request.form['title'], request.form['text'])
                todo.user = g.user
                db.session.add(todo)
                db.session.commit()
                flash('Todo item was successfully created')
                return redirect(url_for('index'))
        return render_template('new.html')

我所拥有的当前代码由各种教程和示例拼凑而成。目前，我正在尝试合并“Todo”数据库，“上传”功能和“新”功能，但收效甚微。使用我所拥有的一点点知识，我只添加了“image_url”部分，其中将是一个用于容纳图像路径的列。如果有人能对这个难题有所了解，我将不胜感激。万分感谢。

尊敬，最大

如何从openhift数据目录上传的文件中获取图像路径/ url以存储在postgresql数据库中？

0 个答案: