Question

我想为一个人创建一个自动GnuPG密钥生成脚本，虽然他们运行ubuntu，但是使用CLI感觉不舒服。此外，其他人管理他们的计算机，使其保持最新和良好的运行顺序，因此他们也没有root / sudo访问权限。而且我真的想尽量避免通过手机上的说明尽可能多地做...已经有太多次知道PITA是什么了！

所以我从gnupg.org论坛上发现的一个例子（我认为？）中大量借用了这个脚本。但是，无论在3或4分钟内生成多少鼠标活动，一旦运行gpg --gen-key --batch命令，它似乎都没有做任何事情。 btw的所有echo语句只是表示脚本进度的临时方法，这不是很远的。

#!/bin/bash

# First run give your server some work, otherwise gpg won't be able to generator random bytes.
#sudo rngd -r /dev/urandom
#no sudo so:
echo -e "\nYou need to begin moving your mouse continuously and in random patterns for as long as it takes to generate a new key. This could take a minute or two, so be patient and just keep moving the mouse.\n"

echo -e "\ngpg --gen-key --batch\n"
gpg --batch --gen-key

%echo Generating a default key
Key-Type: default
Key-Length: 2048
Subkey-Type: default
Name-Real: Firstname Lastname
Name-Comment: No comment
Name-Email: user@domain.com
Expire-Date: 0
Passphrase: abcde
%pubring foo.pub
%secring foo.sec
# Do a commit here, so that we can later print "done" :-)
%commit
%echo done

# kill the rngd task.
#sudo service rng-tools stop


echo -e "\ngpg -k\n"
gpg -k

# get key id for newly created passkey
echo -e "\nkId=$(gpg -k Firstname|grep pub|sed -r 's/^pub[ ]*2048R\/([A-Z0-9]{8,})[ ]*.*$/\1/')\n" #; echo "\$kId: ${kId}"
kId=$(gpg -k Firstname|grep pub|sed -r 's/^pub[ ]*2048R\/([A-Z0-9]{8,})[ ]*.*$/\1/') ; echo -e "\n\$kId: ${kId}\n"

# set key as the default key (if desired) by entering this line in your ~/.bashrc
echo -e "\nexport GPGKEY=$kId\n"
export GPGKEY="$kId"

# restart the gpg-agent and source your .bashrc again
echo -e "\nkillall -q gpg-agent\n"
killall -q gpg-agent
eval $(gpg-agent --daemon)
source ~/.bashrc

#create revocation cert
echo -e "\ngpg --output revoke.asc --gen-revoke $GPGKEY\n"
gpg --output revoke.asc --gen-revoke $GPGKEY

# send public key to keyserver
echo -e "\ngpg --send-keys --keyserver keyserver.ubuntu.com $GPGKEY\n"
#gpg --send-keys --keyserver keyserver.ubuntu.com $GPGKEY

我想知道是否有人可以看到任何明显的问题或遗漏喂养'gpg'所需的关键细节？

即使我使用sudo rngd -r /dev/random命令运行脚本我需要绕过目标用户（没有sudo访问权限），我也会得到同样的东西。

所以我猜问题是在我想要传递给gpg的关键参数中，但我已经用手册页交叉引用它们，似乎无法找到问题所在。虽然gpg没有返回错误，但这很有趣。

Answer 1

通过生成批量密钥，GnuPG期望在文件中创建命令，并与GnuPG manual page on batch key generation进行比较。

cat <<EOT >batch-cmds
%echo Generating a default key
Key-Type: default
Key-Length: 2048
Subkey-Type: default
Name-Real: Firstname Lastname
Name-Comment: No comment
Name-Email: user@domain.com
Expire-Date: 0
Passphrase: abcde
%pubring foo.pub
%secring foo.sec
# Do a commit here, so that we can later print "done" :-)
%commit
%echo done
EOT
gpg --batch --gen-key batch-cmds

考虑将密码存储在硬盘上的文件中的安全隐患。我不确定你是否也可以将内容直接传输到GnuPG而不是将它们存储到文件中。尝试这样的事情：

gpg --batch --gen-key <<EOT
%echo Generating a default key
Key-Type: default
Key-Length: 2048
Subkey-Type: default
Name-Real: Firstname Lastname
Name-Comment: No comment
Name-Email: user@domain.com
Expire-Date: 0
Passphrase: abcde
%pubring foo.pub
%secring foo.sec
# Do a commit here, so that we can later print "done" :-)
%commit
%echo done
EOT

无人参与的GPG命令脚本在GPG命令处挂起

1 个答案: