Question

我有这个按钮单击处理程序（OS X 10.9.3上的MonoMac）：

partial void OnDoButtonClick(NSObject sender)
{
    DoButton.Enabled = false;

    // Start animation
    ProgressIndicator.StartAnimation(this);

    ThreadPool.QueueUserWorkItem(_ => {

        // Perform a task that last for about a second:
        Thread.Sleep(1 * 1000);

        // Stop animation:
        InvokeOnMainThread(() => {
            ProgressIndicator.StopAnimation(this);
            DoButton.Enabled = true;
        });
    });
}

但是，当我按下按钮运行代码时，主线程会停止发生以下错误：

（lldb）退出*线程＃1：tid = 0x2bf20,0x98fd9f7a libsystem_kernel.dylib`mach_msg_trap + 10，queue ='com.apple.main-thread'，stop reason = signal SIGSTOP

并且，以下日志记录在系统日志中：

2014/05/21 13:10:51.752 com.apple.debugserver-310.2[3553]: 1 +0.000001 sec [0de1/1503]: error: ::read ( 0, 0x107557a40, 1024 ) => -1 err = Connection reset by peer (0x00000036)
2014/05/21 13:10:51.752 com.apple.debugserver-310.2[3553]: 2 +0.000001 sec [0de1/0303]: error: ::ptrace (request = PT_THUPDATE, pid = 0x0ddc, tid = 0x1a03, signal = -1) err = Invalid argument (0x00000016)
2014/05/21 13:10:51.753 com.apple.debugserver-310.2[3553]: Exiting.
2014/05/21 13:11:05.000 kernel[0]: process <AppName>[3548] caught causing excessive wakeups. Observed wakeups rate (per sec): 1513; Maximum permitted wakeups rate (per sec): 150; Observation period: 300 seconds; Task lifetime number of wakeups: 45061
2014/05/21 13:11:05.302 ReportCrash[3555]: Invoking spindump for pid=3548 wakeups_rate=1513 duration=30 because of excessive wakeups
2014/05/21 13:11:07.452 spindump[3556]: Saved wakeups_resource.spin report for <AppName> version 1.2.1.0 (1) to /Library/Logs/DiagnosticReports/<AppName>_2014-05-21-131107_<UserName>-MacBook-Pro.wakeups_resource.spin

从上面摘录：Maximum permitted wakeups rate (per sec): 150; Observation period: 300 seconds; Task lifetime number of wakeups: 45061

如果我删除ProgressIndicator.StartAnimation(this);和ProgressIndicator.StopAnimation(this);行，则不会发生此问题。

为什么主线程被SIGSTOP停止？

简单的Mac ProgressIndicator导致崩溃：＆＃34;陷入导致过度唤醒＆＃34;

0 个答案: