Question

控制器代码

$rates['poor'] = 10; 
$rates['fair'] = 20;

$this->load->view('search_result2', $rates);

//I have tried this in many ways but at least It executes the "success" in ajax file only with above way.  other ways I have tried ex :-
//$this->output->set_output(json_encode($rates));
//echo json_encode($rates);

我需要将此费率数组传递给ajax

js code

$.ajax({
    type:'POST',
    url:'some url',
    data:{'adID':adID},
    //dataType:'JSON', // when I uncommented this it displays nothing. when commented it displays "undefined" on the label below i have created
    success:function(rates){ 

        $('#rate_val').html('<label>'+rates.poor+'</label>');

        //I have tried this in many ways  ex :-
        // $('#rate_val').html('<label>'+rates['poor']+'</label>');
        // $('#rate_val').html('<label>'+rates[0]+'</label>');

    }
});

这会在标签上显示“undefined”。我无法获取从控制器传递的数据。请帮忙吗？

Answer 1

取消注释dataType:'JSON'
使用来自控制器

echo

set_output

从ajax

rates.poor

rates['poor']

<强>控制器

public function post_url()
{
    $rates = array();
    $rates['poor'] = 10; 
    $rates['fair'] = 20;

    $this->output->set_output(json_encode($rates));
}

<强>的Ajax

<script>
$.ajax({
    type:'POST',
    url:'POST_URL',
    data:{'adID':adID},
    dataType:'JSON',
    success:function(rates){ 
        $('#rate_val').html('<label>'+rates.poor+'</label>');
    }
});
</script>

Answer 2

$data['a']='100';
$data['b']='200';
echo json_encode(array('success'=>$data));

jquery的

<script>
$.ajax({
    type:'POST',
    url:'POST_URL',
    data:{'adID':adID},
    dataType:'JSON',
    success:function(rates){
       var data     = jQuery.parseJSON('['+response+']');

        $('#rate_val').html('<label>'+data.succcess.a+'</label><label>'+data.succcess.b+'</label>');
    }
});
</script>

我相信它可以按你的意愿执行。

如何在codeigniter中将数据从控制器传递到jquery（Ajax）

2 个答案: