Question

我想将位图转换为URI转换我正在使用来自此API的谷歌图片搜索API我从此URL获取了图像URL我将其转换为位图然后我想使用此示例从此位图转换为URI但我得到空值。

private class GetXMLTask extends AsyncTask<String, Void, Bitmap> {
    @Override
    protected Bitmap doInBackground(String... urls) {
        Bitmap map = null;
        for (String url : urls) {
            map = downloadImage(url);
        }
        return map;
    }

    // Sets the Bitmap returned by doInBackground
    @Override
    protected void onPostExecute(Bitmap result) {

        imagQest.setImageBitmap(result);

        ByteArrayOutputStream bytes = new ByteArrayOutputStream();
        result.compress(Bitmap.CompressFormat.JPEG, 100, bytes);
        String path = Images.Media.insertImage(ctx.getContentResolver(),
                result, "Title", null);
        LivLog.info(this.getClass(), "bit map conversion is" + result
                + path);

    }

    // Creates Bitmap from InputStream and returns it
    private Bitmap downloadImage(String url) {
        Bitmap bitmap = null;
        InputStream stream = null;
        BitmapFactory.Options bmOptions = new BitmapFactory.Options();
        bmOptions.inSampleSize = 1;

        try {
            stream = getHttpConnection(url);
            bitmap = BitmapFactory.decodeStream(stream, null, bmOptions);
            // stream.close();
        } catch (IOException e1) {
            e1.printStackTrace();
        }
        return bitmap;
    }

    // Makes HttpURLConnection and returns InputStream
    private InputStream getHttpConnection(String urlString)
            throws IOException {
        InputStream stream = null;
        URL url = new URL(urlString);
        URLConnection connection = url.openConnection();

        try {
            HttpURLConnection httpConnection = (HttpURLConnection) connection;
            httpConnection.setRequestMethod("GET");
            httpConnection.connect();

            if (httpConnection.getResponseCode() == HttpURLConnection.HTTP_OK) {
                stream = httpConnection.getInputStream();
            }
        } catch (Exception ex) {
            ex.printStackTrace();
        }
        return stream;
    }
}

如何解决这个问题？

Answer 1

尝试以下代码： -

public Uri getImageUri(Context inContext, Bitmap inImage) {
  ByteArrayOutputStream bytes = new ByteArrayOutputStream();
  inImage.compress(Bitmap.CompressFormat.JPEG, 100, bytes);
  String path = Images.Media.insertImage(inContext.getContentResolver(), inImage, "Title", null);
  return Uri.parse(path);
}

了解更多信息，请参阅以下链接： -

http://colinyeoh.wordpress.com/2012/05/18/android-getting-image-uri-from-bitmap/

Answer 2

这是将位图转换为Uri的方法：

private Uri getImageUri(Context context, Bitmap inImage) {
    ByteArrayOutputStream bytes = new ByteArrayOutputStream();
    inImage.compress(Bitmap.CompressFormat.JPEG, 100, bytes);
    String path = MediaStore.Images.Media.insertImage(context.getContentResolver(), inImage, "Title", null);
    return Uri.parse(path);
}

在调用此方法时传递位图：

getImageUri(this,bitmap);

位图到uri转换android？

2 个答案: