编辑：

Question

我试图这样做：

$.ajax({
    type:"POST",
    url:"/psychos",
    data:JSON.stringify(this.psycho)        
})

在服务器上我得到了：

app.post("/psychos", function(request, response) {

    var psychologist = request.body.psycho
    console.log(psychologist)


    psicologosCollection.insert(psychologist, function(error, responseFromDB) {

        if (error) {response.send(responseFromDB)}

        console.log("Se ha insertado: "+ JSON.strinfigy(responseFromDB))
        response.send(responseFromDB)
    })
})

但是，console.log()正在打印undefined并得到以下投掷：

TypeError: Cannot read property '_id' of undefined
    at insertWithWriteCommands (/home/diegoaguilar/DigitalOcean/psicologostuxtepec/node_modules/mongodb/lib/mongodb/collection/core.js:78:13)
    at Collection.insert (/home/diegoaguilar/DigitalOcean/psicologostuxtepec/node_modules/mongodb/lib/mongodb/collection/core.js:30:7)
    at Object.handle (/home/diegoaguilar/DigitalOcean/psicologostuxtepec/server.js:117:25)
    at next_layer (/home/diegoaguilar/DigitalOcean/psicologostuxtepec/node_modules/express/lib/router/route.js:103:13)
    at Route.dispatch (/home/diegoaguilar/DigitalOcean/psicologostuxtepec/node_modules/express/lib/router/route.js:107:5)
    at c (/home/diegoaguilar/DigitalOcean/psicologostuxtepec/node_modules/express/lib/router/index.js:195:24)
    at Function.proto.process_params (/home/diegoaguilar/DigitalOcean/psicologostuxtepec/node_modules/express/lib/router/index.js:251:12)
    at next (/home/diegoaguilar/DigitalOcean/psicologostuxtepec/node_modules/express/lib/router/index.js:189:19)
    at next (/home/diegoaguilar/DigitalOcean/psicologostuxtepec/node_modules/express/lib/router/index.js:166:38)
    at Layer.session [as handle] (/home/diegoaguilar/DigitalOcean/psicologostuxtepec/node_modules/express-session/index.js:98:29)

我之前使用 BodyParser ：

var bodyParser  = require('body-parser')
app.use(bodyParser())

psycho实际上是一个有效的现有对象。在执行AJAX的方法中，console.log(this.psycho)将打印我的对象。我做错了什么？

编辑：

即使我发现我应该得到：

var psychologist = request.body.psycho

在服务器GET路由代码中，我无法理解bodyParser如何生成一个Object？

对于我之前尝试的非常类似的AJAX调用：

function getSendingJSON(url,reqObject,callBack)  {
    $.ajax({
        type: "get",
        data: reqObject,
        dataType: "json",
        url: url,
        success: function(response){
           callBack(response);
        }
    });
}

因此响应是JSON，回调函数类似于：

function plotReglaFalsa(respuesta) {

    if (respuesta.fail) {...}
    else if (respuesta.negative) {...}
    ....
}

即使这纯粹是在客户端，我也很困惑如何处理Objects / JSON序列化以及bodyParser如何处理它。

Answer 1

您没有将请求中的数据序列化，它仍然只是一个JavaScript对象，直到您将其序列化为JSON：

$.ajax({
    type:"POST",
    contentType: "application/json",
    url:"/psychos",
    data: JSON.stringify( this.pyscho )
})

所以调用JSON.stringify以序列化为JSON，然后身体解析器有解析的东西。

Answer 2

app.post("/psychos", function(request, response) {
 //change request.body.psycho to request.body
 var psychologist = request.body
 console.log(psychologist)
 psicologosCollection.insert(psychologist, function(error, responseFromDB) {

 if (error) {response.send(responseFromDB)}

    console.log("Se ha insertado: "+ JSON.stringify(responseFromDB))
    response.send(responseFromDB)
})
})

如何使用node.js中的bodyParser通过AJAX正确发送对象？

编辑：

2 个答案: