Question

我试图让php ajax搜索数据库中发布的文章，但它只给我：没有结果消息。我已经测试了与数据库和选择查询的连接，并且它可以工作。这是代码：

<?php
require_once('dbconn.php');
$s = $_GET["s"];
$livesearch = '';
if (strlen($s) > 0)

{
    $result = mysql_query("select * from articles where art_sts='1' ORDER BY title"); 
    if ($result != FALSE)
    {
        foreach($result as $row)
        {
            if (stristr($row['title'], $s))
            {
                if ($livesearch == '')
                {
                    $livesearch = '<a href="upload_pdf/'.$row["fisier"].'?id='.$row["id"].' "> '.htmlentities($row["title"], ENT_QUOTES, "UTF-8").'</a>';
                }
            }
        }
    }

}

if ($livesearch == '')
{
    $respond="No results...";
}
else
{
$respond = $livesearch;
}
echo $respond;
?>

Answer 1

您实际上并未提取您要输出的数据。你需要添加这样的东西......

while($row = mysql_fetch_assoc($result)) {
     if (stristr($row['title'], $s))
        {
            if ($livesearch == '')
            {
                $livesearch = '<a href="upload_pdf/'.$row["fisier"].'?id='.$row["id"].' "> '.htmlentities($row["title"], ENT_QUOTES, "UTF-8").'</a>';
            }
        }
}

php ajax搜索不显示结果

1 个答案: