Question

我正在尝试将格式化添加到所有/ * TODO：... * /标签，但我在多行区域遇到问题。我可以做单线sed;但对于多线sed和awk，我不知道。

我该怎么做？我愿意接受。这是我到目前为止所拥有的。

sed 's/\/\/\*[ \t]*TODO[ \t]*:.*/*\//<span style="color:#aaaaaa;font-weight:bold;">&</span>/g'

替换：

int void main ( int h, char * argv[] )
  int a, b; /* TODO :
               - include libraries
               ...
            */
  foobar();
  /* TODO : fix missing {'s */

with：

int void main ( int h, char * argv[] )
  int a, b; <span style="color:#aaaaaa; font-weight:bold;">/* TODO :
               - include libraries
               ...
            */</span>
  foobar();
  <span style="color:#aaaaaa; font-weight:bold;">/* TODO : fix missing {'s */ </span>

Answer 1

gawk 'BEGIN{
  RS="*/"
  replace="<span style=\"color:#aaaaaa; font-weight:bold;\">"
}
/\/\* +TODO/{
    gsub(/\/\* +TODO/,replace" /* TODO")
    RT=RT "</span>"
}
{ print $0RT}
' file

输出

$ ./shell.sh
int void main ( int h, char * argv[] )
  int a, b; <span style="color:#aaaaaa; font-weight:bold;"> /* TODO :
               - include libraries
               ...
            */</span>

  foobar();
  <span style="color:#aaaaaa; font-weight:bold;"> /* TODO : fix missing {'s */</span>

sed或awk多行替换

1 个答案: