Question

我有一个问题，在一个文件中我有这个：

plot1:
    8 lines of content
plot2:
    8 lines of content
plot3:
    8 lines of content
plot4:
    8 lines of content
plot5:
    8 lines of content
plot6:
    8 lines of content
plot7:
    8 lines of content
plot8:
    8 lines of content
plot9:
    8 lines of content
plot10:
    8 lines of content
plot11:
    8 lines of content
plot12:
    8 lines of content
plot13:
    8 lines of content
plot14:
    8 lines of content
plot15:
    8 lines of content
plot16:
    8 lines of content
plot17:
    8 lines of content
plot18:
    8 lines of content
plot19:
    8 lines of content
plot20:
    8 lines of content
plot21:
    8 lines of content
plot22:
    8 lines of content
plot23:
    8 lines of content
plot24:
    8 lines of content
plot25:
    8 lines of content
plot26:
    8 lines of content
plot27:
    8 lines of content
plot28:
    8 lines of content
plot29:
    8 lines of content

我希望能够选择一个数字来替换字图旁边的数字1并递增到结尾。因此，例如用60替换1并获得plot60直到plot89。

Answer 1

@echo off 
    setlocal enableextensions disabledelayedexpansion 

    (for /f "delims=" %%a in (file.txt
    ) do for /f "tokens=2 delims=1234567890 " %%b in ("%%~a"
    ) do if not "%%b"==":"  (
        echo(%%~a
    ) else for /f "tokens=1 delims=plot:" %%c in ("%%~a"
    ) do (
        set /a "n=%%c+59"
        setlocal enabledelayedexpansion
        echo(plot!n!:
        endlocal
    )) > out.txt

批量 - 在文本后替换数字

1 个答案: