Question

如何使这段代码更简单？

if (PlayersLevel > 1)
    button4.Visible = true;        
else
    button4.Visible = false;

if (PlayersLevel > 2)
    button5.Visible = true;
else
    button5.Visible = false;

好的，好的，我已经知道=）谢谢

Answer 1

只需将值设置为比较结果：

button4.Visible = PlayersLevel > 1;
button5.Visible = PlayersLevel > 2;

Answer 2

button4.Visible = (PlayersLevel > 1);
button5.Visible = (PlayersLevel > 2);

Answer 3

您不需要If语句，您将获得True / False以下

button4.Visible = PlayersLevel > 1;        
button5.Visible = PlayersLevel > 2;

Answer 4

一个小的Linq封装使故意代码不能伤害。放入此扩展方法

public static void VisibleWhen( this Button button , bool visibilityState )
{
  button.Visible = visibilityState ;
}

然后你可以说：

button4.VisibleWhen( PlayersLevel > 1 ) ;
button4.VisibleWhen( PlayersLevel > 2 ) ;

Answer 5

你可以使用Bool的结果。

button4.Visible = PlayersLevel > 1;        
button5.Visible = PlayersLevel > 2;

Answer 6

button4.Visible = PlayersLevel > 1;
button5.Visible = PlayersLevel > 2

Answer 7

另一种方法：

button4.visible = PlayersLevel > 1 ? true : false;
button5.visible = PlayersLevel > 2 ? true : false;

如何使代码更简单（if / else）

7 个答案: