Android EditText光标"鬼魂"

时间:2014-05-20 16:22:26

标签: android android-edittext

我只是偶尔的Android程序员,似乎无法找到答案。我猜我设置错了。我的应用程序在模拟器中工作正常,但当我移动到设备时,

T | E | X | T |升| O | O | K | S |升| I | K | E | T | H | I | S |

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我输入的时候。我的代码如下,此时非常简单......

xml中的EditText

<EditText
    android:id="@+id/server_username"
    android:layout_width="match_parent"
    android:layout_height="wrap_content"
    android:ems="10"
    android:inputType="text" />

MainActivity.java

public class MainActivity extends Activity {

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);

    setContentView(R.layout.activity_main);

    final Button clickButton = (Button) findViewById(R.id.save_button);
    final EditText serverUrl = (EditText)findViewById(R.id.server_url);
    final EditText serverUsername = (EditText)findViewById(R.id.server_username);
    final EditText serverPassword = (EditText)findViewById(R.id.server_password);


    clickButton.setOnClickListener( new OnClickListener() {

                @Override
                public void onClick(View arg0) {
                    String url = serverUrl.getText().toString();

                    String username = serverUsername.getText().toString();

                    String password = serverPassword.getText().toString();

                    ContentValues values = new ContentValues();

                    values.put(CredentialsProvider.SERVERURL, url);

                    values.put(CredentialsProvider.USERNAME, username);

                    values.put(CredentialsProvider.PASSWORD, password);

                    getContentResolver().update(
                    CredentialsProvider.CONTENT_URI, values, null, null);

                }
     });

      String URL = "content://com.dont.touch.jobus.rum/credentials/1";
      Uri creds = Uri.parse(URL);
      Cursor c =getContentResolver().query(creds, null, null, null, "username");
      if (c.moveToPosition(0)) {
          serverUrl.setText(c.getString(c.getColumnIndex( CredentialsProvider.SERVERURL)));
          serverUsername.setText(c.getString(c.getColumnIndex( CredentialsProvider.USERNAME)));
         serverPassword.setText(c.getString(c.getColumnIndex( CredentialsProvider.PASSWORD)));

      } else {
          ContentValues values = new ContentValues();

          values.put(CredentialsProvider.SERVERURL, 
                  "not configured");

          values.put(CredentialsProvider.USERNAME, 
                  "not configured");

          values.put(CredentialsProvider.PASSWORD, 
                  "not configured");

          getContentResolver().insert(
                  CredentialsProvider.CONTENT_URI, values);
      }
}

@Override
protected void onPostCreate(Bundle savedInstanceState) {
    super.onPostCreate(savedInstanceState);

}

}

0 个答案:

没有答案